Suppose a program is designed to count the number of characters excluding spaces, periods, exclamation marks, and commas in a string of given text. For example, the user may input a string such as : 'Listen, Mr. Jones, calm down.' Which for loop will give the correct result? char_count = 0 for character in user_text: if (character !='') and (character != '.') and (character != ',') and (character != '!'): char_count += 1 char_count = 0 for character in user_text: if (character ==') and (character == '.') and (character == ',') and (character == '!'): char_count += 1 char_count = 0 for character in user_text: if (character !='') or (character != '.') or (character != ',') or (character != '!'): char_count += 1 None of the above

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Suppose a program is designed to count the number of characters excluding spaces,
periods, exclamation marks, and commas in a string of given text. For example, the
user may input a string such as :
'Listen, Mr. Jones, calm down.'
Which for loop will give the correct result?
char_count = 0
for character in user_text:
if (character !='') and (character != '.') and (character != ',') and (character != '!'):
char_count += 1
char_count = 0
for character in user_text:
if (character
:') and (character
'.') and (character
',;') and (character
'!'):
==
==
==
==
char_count += 1
char_count = 0
O for character in user_text:
if (character != '') or (character != '.') or (character != ',') or (character != '!'):
char_count += 1
None of the above
Transcribed Image Text:Suppose a program is designed to count the number of characters excluding spaces, periods, exclamation marks, and commas in a string of given text. For example, the user may input a string such as : 'Listen, Mr. Jones, calm down.' Which for loop will give the correct result? char_count = 0 for character in user_text: if (character !='') and (character != '.') and (character != ',') and (character != '!'): char_count += 1 char_count = 0 for character in user_text: if (character :') and (character '.') and (character ',;') and (character '!'): == == == == char_count += 1 char_count = 0 O for character in user_text: if (character != '') or (character != '.') or (character != ',') or (character != '!'): char_count += 1 None of the above
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