Suppose an electron (q= - e= - 1.6 × 10¯19 C,m=9.1× 10¯³ª kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures.

Physics for Scientists and Engineers
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Author:Raymond A. Serway, John W. Jewett
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Chapter24: Electric Potential
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Problem 1P: How much work is done (by a battery, generator, or some other source of potential difference) in...
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QUESTION 1
Suppose an electron (q = - e = - 1.6 x 10-19 C ,m=9.1 x 10¯' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for
the final speed of the electron. Express numerical answer in two significant figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K +U = 0
K = -U
Since K =
- mv and using the formula for potential energy above, we arrive at an equation for speed:
V = (
1/2
Plugging in values, the value of the electron's speed is:
x 107 m/s
V=
Transcribed Image Text:QUESTION 1 Suppose an electron (q = - e = - 1.6 x 10-19 C ,m=9.1 x 10¯' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K +U = 0 K = -U Since K = - mv and using the formula for potential energy above, we arrive at an equation for speed: V = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=
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