Suppose B > A > 0, meaning that each bij > aij > 0. How does the PerronFrobenius discussion show that Amax(B) > Amax(A)?
Suppose B > A > 0, meaning that each bij > aij > 0. How does the PerronFrobenius discussion show that Amax(B) > Amax(A)?
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section: Chapter Questions
Problem 9RQ
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Suppose B > A > 0, meaning that each bij > aij > 0. How does the PerronFrobenius discussion show that Amax(B) > Amax(A)?
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