Suppose data is found showing the demand for a product and its price (in dollars) in different market aroas where the demand values ranged from 18 to 90. Furthermore, the goal is to use the data to construct a model that will be used to predict the price for the product in terms of its demand. Further, suppose the regression line is found to be y = 23.51535 -0.09035z The price for the product when the demand is 160 is: The average price is 23.51535 - 0.09035(160) = $9.06 anytime the demand is 160 The average price is 23.51535 -0.09035(160) = $0.06 for this specific timo that the demand is 160 The price is 23 51535-0.09035(160) $9 06 anytime the demand is 60 The price is 23.51535 - 0.09035(160) = $0.06 for this specific time that the demand is 60 The answer cannot be found due to extrapolation

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter1: Equations And Graphs
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Suppose data is found showing the demand for a product and its price (in dollars) in different market areas where the demand
values ranged from 18 to 90. Furthermore, the goal is to use the data to construct a model that will be used to predict the price
for the product in terms of its demand. Further, suppose the regression line is found to be y = 23.51535 – 0.09035z The-
price for the product when the demand is 160 is:
O The average price is 23.51535 - 0.09035(160) = $9.06 anytime the demand is 160
O The average price is 23.51535 - 0.09035(160) = $9.06 for this specific time that the demand is 160
O The price is 23.51535 - 0. 09035(160) = $9 06 anytime the demand is 60
The price is 23.51535 - 0.09035(160) = $9.06 for this specific time that the demand is 60
O The answer cannot be found due to extrapolation
Transcribed Image Text:Suppose data is found showing the demand for a product and its price (in dollars) in different market areas where the demand values ranged from 18 to 90. Furthermore, the goal is to use the data to construct a model that will be used to predict the price for the product in terms of its demand. Further, suppose the regression line is found to be y = 23.51535 – 0.09035z The- price for the product when the demand is 160 is: O The average price is 23.51535 - 0.09035(160) = $9.06 anytime the demand is 160 O The average price is 23.51535 - 0.09035(160) = $9.06 for this specific time that the demand is 160 O The price is 23.51535 - 0. 09035(160) = $9 06 anytime the demand is 60 The price is 23.51535 - 0.09035(160) = $9.06 for this specific time that the demand is 60 O The answer cannot be found due to extrapolation
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