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- The result of the following is __.string str = "jlo@testmail.com";string newStr = "";string[] tokens = str.Split('@');foreach (string s in tokens){newStr += s;}MessageBox.Show(newStr); jlo@testmail.com jlotestmail.com jlotestmailcom jloI ran the code and this is the error I got. Make sure to take screenshots of the output. Please add the following state machines and produce the same output: private Token processWord() { StringBuilder value = new StringBuilder(); while (!stringHandler.isDone() && (Character.isLetterOrDigit(stringHandler.peek(0)) || stringHandler.peek(0) == '_' || stringHandler.peek(0) == ',')) { value.append(stringHandler.getChar()); charPosition++; } return new Token(TokenType.WORD, value.toString(), lineNumber, charPosition - value.length()); } private Token processNumber() { StringBuilder value = new StringBuilder(); while (!stringHandler.isDone() && (Character.isDigit(stringHandler.peek(0)) || stringHandler.peek(0) == '.')) { value.append(stringHandler.getChar()); charPosition++; } return new Token(TokenType.NUMBER, value.toString(), lineNumber, charPosition -…Consider the following snippet of code? double interestOnLoan 19.35; double loanAmount = 100.25; int totalAmount = 0; totalAmount = (loanAmount + interestOnLoan); What is the final totalAmount equal to?
- Suppose s is a string with the value "java". What will be assigned to x if you execute the following code? char x = s.charAt(4);Many user-created passwords are simple and easy to guess. Write a program that takes a simple password and makes it stronger by replacing characters using the key below, and by appending "!" to the end of the input string. i becomes 1 a becomes @ m becomes M B becomes 8 s becomes $ Ex: If the input is: mypassword the output is: Myp@$$word! word = input()password = '' ''' Type your code here. '''Many user-created passwords are simple and easy to guess. Write a program that takes a simple password and makes it stronger by replacing characters using the key below, and by appending "q*s" to the end of the input string. i becomes ! a becomes @ m becomes M B becomes 8 o becomes . Ex: If the input is: mypassword the output is: Myp@ssw.rdq*s How do I write this in C++
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- what should I add to make it reject a number? and ask the user to not enter a number by displaying "Syllable must only contain letters or a wildcard" def add_gibberish(word, gib1, gib2):vowels = "AaEeIiOoUu"flag = Truelast = Falsei = 0while (i < len(word)): #traverse whole wordif word[i] in vowels: # if character in a word is vowelif last == False: # if last charcater was not vowelif flag == True: #check if first occurence of vowelword = word[0:i] + gib1 + word[i:len(word)] #add gibberish to the wordi = i + len(gib1) + 1flag = Falselast = Trueelse:word = word[0:i] + gib2 + word[i:len(word)] # if other than first occurence of voweli = i + len(gib2) + 1last = Trueelse:i = i + 1else: # if character is not vowellast = False # set last character was not voweli = i + 1; return word def start():gib1 = input("Enter first gibberish syllable: ")gib2 = input("Enter second gibberish syllable: ")word = input("Enter a word to translate: ")new_word = add_gibberish(word, gib1,…Suppose s1 and s2 are two strings. Which of the following statement or expression is valid in Java ? a - String s3 = s1 + s2; b - s1 >= s2; c - int i = s1.length; d - s1.charAt(0) = '5';Explain how the given program works. using System; class Program{ static void Main() { string text = "civic"; string reverse = ""; bool result; for(int x = text.Length - 1; x >= 0; x--){ reverse = reverse + text[x]; } result = text.Equals(reverse, StringComparison.CurrentCultureIgnoreCase) ? true:false; Console.WriteLine("Given text: {0}", text); Console.WriteLine("Reverse text: {0}", reverse); Console.WriteLine("Result: {0}", result); }}