Suppose that (1) Randy is heterozygous for the allele that causes Huntington's disease, (2) Susan is homozygous recessive for the allele that causes Huntington's disease, and (3) Randy and Susan decide to have achild. What is the probability that their child will get Hunting- ton's disease? a. 100% b. 75% c. 50% d. 25% e. 0% 5. In question 4, what is the probability that their first daughter will get Huntington's disease? a. 100% b. 75% c. 50% d. 25% e. 0%
Suppose that (1) Randy is heterozygous for the allele that causes Huntington's disease, (2) Susan is homozygous recessive for the allele that causes Huntington's disease, and (3) Randy and Susan decide to have achild. What is the probability that their child will get Hunting- ton's disease? a. 100% b. 75% c. 50% d. 25% e. 0% 5. In question 4, what is the probability that their first daughter will get Huntington's disease? a. 100% b. 75% c. 50% d. 25% e. 0%
Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Chapter12: Mendel, Genes, And Inheritance
Section12.2: Later Modifications And Additions To Mendel’s Principles
Problem 2SB: A true-breeding rabbit with agouti (mottled, grayish brown) fur crossed with a true-breeding rabbit...
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4. Suppose that (1) Randy is heterozygous for the allele
that causes Huntington's disease, (2) Susan is
homozygous recessive for the allele that causes
Huntington's disease, and (3) Randy and Susan decide
to have achild. What is the probability that their child
will get Hunting- ton's disease?
a. 100% b. 75% c. 50% d. 25% e. 0%
5. In question 4, what is the probability that their first
daughter will get Huntington's disease?
a. 100% b. 75% c. 50% d. 25% e. 0%
i really just need number 5.
thank you
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