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Suppose that A, B, and C are vertices of a triangle and that a, b, and c are, respectively, the midpoints of the opposite sides. Show that Aa + Bb + Cc = 0. XB +XC A. YB +Yc Z8 +Zc -XAI+ YA I+ k ZA +Zc k 2 XA +Xc OB. YA+Yc i+ j+ 2 (XA+Xc (YA+Yc i+ ZA +Zc -YB i+ ZB k XB Ув Find Cc. Choose the correct answer below. XA + XB YA+ YB ZA +ZB Xci+ --Ycj+ 2 ZA + ZB k XA+Xg YA+YB i+ 2 Ус OC. Xg + XC YB+Yc i+ (Zg +2c j+ OD. -YA 2 Compute Aa + Bb + Cc using the component forms found above. Aa + Bb + Cc = (Simplify your answers.) Textbook Ask my instructor

Suppose that A, B, and C are vertices of a triangle and that a, b, and c are, respectively, the midpoints of the opposite sides. Show that Aa + Bb + Cc = 0. XB +XC A. YB +Yc Z8 +Zc -XAI+ YA I+ k ZA +Zc k 2 XA +Xc OB. YA+Yc i+ j+ 2 (XA+Xc (YA+Yc i+ ZA +Zc -YB i+ ZB k XB Ув Find Cc. Choose the correct answer below. XA + XB YA+ YB ZA +ZB Xci+ --Ycj+ 2 ZA + ZB k XA+Xg YA+YB i+ 2 Ус OC. Xg + XC YB+Yc i+ (Zg +2c j+ OD. -YA 2 Compute Aa + Bb + Cc using the component forms found above. Aa + Bb + Cc = (Simplify your answers.) Textbook Ask my instructor

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter1: Vectors
Section: Chapter Questions
Problem 4RQ
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Suppose that A, B, and C are vertices of a triangle and that a, b, and c are, respectively, the midpoints of the opposite sides. Show that Aa + Bb + Cc = 0. (Ув+Ус ZB +Zc XB + XC O A. i+ -XA -YA -2A XA + Xc O B. ZA +Zc k YA+Yc i+ j+- 2. XA + XC (YA+Yc (ZA+Zc - ZB CC. - XB i+ 2 -YB j+ 2 2 ZB j+ XB Ув i+ 2 OD. Find Cc. Choose the correct answer below. XA + XB YA+ YB ZA + ZB Xci+ Yc j+ OB. XA+XB YA +YB i+ ZA + ZB k 2 XC -i+ OD. XB + XC - XA (YB +Yc i+ Zg +Zc j+ -YA - ZA Compute Aa + Bb + Cc using the component forms found above. i+i+k Aa + Bb + Cc = (Simplify your answers.) Textbook Ask my instructor
Transcribed Image Text:Suppose that A, B, and C are vertices of a triangle and that a, b, and c are, respectively, the midpoints of the opposite sides. Show that Aa + Bb + Cc = 0. (Ув+Ус ZB +Zc XB + XC O A. i+ -XA -YA -2A XA + Xc O B. ZA +Zc k YA+Yc i+ j+- 2. XA + XC (YA+Yc (ZA+Zc - ZB CC. - XB i+ 2 -YB j+ 2 2 ZB j+ XB Ув i+ 2 OD. Find Cc. Choose the correct answer below. XA + XB YA+ YB ZA + ZB Xci+ Yc j+ OB. XA+XB YA +YB i+ ZA + ZB k 2 XC -i+ OD. XB + XC - XA (YB +Yc i+ Zg +Zc j+ -YA - ZA Compute Aa + Bb + Cc using the component forms found above. i+i+k Aa + Bb + Cc = (Simplify your answers.) Textbook Ask my instructor
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