Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at BC bookstore costs $$ 68.59. You want to test this claim. The null and alternative hypothesis in symbols would be: H0:μ≤68.59H0:μ≤68.59 H1:μ>68.59H1:μ>68.59 H0:p=68.59H0:p=68.59 H1:p≠68.59H1:p≠68.59 H0:p≤68.59H0:p≤68.59 H1:p>68.59H1:p>68.59 H0:μ=68.59H0:μ=68.59 H1:μ≠68.59H1:μ≠68.59 H0:p≥68.59H0:p≥68.59 H1:p<68.59H1:p<68.59 H0:μ≥68.59H0:μ≥68.59 H1:μ<68.59H1:μ<68.59 The null hypothesis in words would be: The average price of textbooks in a sample is $$ 68.59 The average of price of all textbooks from the store is less than $$ 68.59. The average of price of all textbooks from the store is greater than $$ 68.59. The average price of all textbooks from the store is $$ 68.59 The proportion of all textbooks from the store that are less than 68.59 is equal to 50% Based on a sample of 100 textbooks at the store, you find an average of 70.39 and a standard deviation of 29.6. The point estimate is: __ (to 3 decimals) The 90 % confidence interval (use z*) is: __ to __ (to 3 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at BC bookstore costs $$ 68.59. You want to test this claim. The null and alternative hypothesis in symbols would be: H0:μ≤68.59H0:μ≤68.59 H1:μ>68.59H1:μ>68.59 H0:p=68.59H0:p=68.59 H1:p≠68.59H1:p≠68.59 H0:p≤68.59H0:p≤68.59 H1:p>68.59H1:p>68.59 H0:μ=68.59H0:μ=68.59 H1:μ≠68.59H1:μ≠68.59 H0:p≥68.59H0:p≥68.59 H1:p<68.59H1:p<68.59 H0:μ≥68.59H0:μ≥68.59 H1:μ<68.59H1:μ<68.59 The null hypothesis in words would be: The average price of textbooks in a sample is $$ 68.59 The average of price of all textbooks from the store is less than $$ 68.59. The average of price of all textbooks from the store is greater than $$ 68.59. The average price of all textbooks from the store is $$ 68.59 The proportion of all textbooks from the store that are less than 68.59 is equal to 50% Based on a sample of 100 textbooks at the store, you find an average of 70.39 and a standard deviation of 29.6. The point estimate is: __ (to 3 decimals) The 90 % confidence interval (use z*) is: __ to __ (to 3 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 1E
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Question
Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at BC bookstore costs $$ 68.59. You want to test this claim.
The null and alternative hypothesis in symbols would be:
- H0:μ≤68.59H0:μ≤68.59
H1:μ>68.59H1:μ>68.59 - H0:p=68.59H0:p=68.59
H1:p≠68.59H1:p≠68.59 - H0:p≤68.59H0:p≤68.59
H1:p>68.59H1:p>68.59 - H0:μ=68.59H0:μ=68.59
H1:μ≠68.59H1:μ≠68.59 - H0:p≥68.59H0:p≥68.59
H1:p<68.59H1:p<68.59 - H0:μ≥68.59H0:μ≥68.59
H1:μ<68.59H1:μ<68.59
The null hypothesis in words would be:
- The average price of textbooks in a sample is $$ 68.59
- The average of price of all textbooks from the store is less than $$ 68.59.
- The average of price of all textbooks from the store is greater than $$ 68.59.
- The average price of all textbooks from the store is $$ 68.59
- The proportion of all textbooks from the store that are less than 68.59 is equal to 50%
Based on a sample of 100 textbooks at the store, you find an average of 70.39 and a standard deviation of 29.6.
The point estimate is: __ (to 3 decimals)
The 90 % confidence interval (use z*) is: __ to __ (to 3 decimals)
Based on this we:
- Reject the null hypothesis
- Fail to reject the null hypothesis
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