Suppose that P(A|B)=0.4 and P(B)=0.5. What is P(A B)?

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter2: The Integers
Section2.7: Introduction To Coding Theory (optional)
Problem 6E: Suppose the probability of erroneously transmitting a single digit is P=0.03. Compute the...
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Question
Suppose that P(A|B)=0.4 and P(B)=0.5. What is
P(A
B)?
0.8
O 0.2
O 0.1
D Question 5
ts
Computer keyboard failures are due to faulty
electrical connects (12%) or mechanical defects
(88%). Mechanical defects are related to loose
keys (27%) or improper assembly (73%).
Electrical connect defects are caused by
defective wires (35%),
proper connections
(13%), or poorly welded wires (52%).
Find the probability that a failure is due to loose
keys.
O 0.2376
O 0.306
Transcribed Image Text:Suppose that P(A|B)=0.4 and P(B)=0.5. What is P(A B)? 0.8 O 0.2 O 0.1 D Question 5 ts Computer keyboard failures are due to faulty electrical connects (12%) or mechanical defects (88%). Mechanical defects are related to loose keys (27%) or improper assembly (73%). Electrical connect defects are caused by defective wires (35%), proper connections (13%), or poorly welded wires (52%). Find the probability that a failure is due to loose keys. O 0.2376 O 0.306
defective wires (35%), improper connections
(13%), or poorly welded wires (52%).
Find the probability that a failure is due to loose
keys.
0.2376
0.306
0.3698
D Question 6
An e-mail filter is planned to separate valid e-
mails from spam. The word free occurs in 60%
of the spam messages and only 4% of the valid
messages. Also, 20% of the messages are spam.
Determine the probability that the message
contains free.
0.12
0.152
0.60
Transcribed Image Text:defective wires (35%), improper connections (13%), or poorly welded wires (52%). Find the probability that a failure is due to loose keys. 0.2376 0.306 0.3698 D Question 6 An e-mail filter is planned to separate valid e- mails from spam. The word free occurs in 60% of the spam messages and only 4% of the valid messages. Also, 20% of the messages are spam. Determine the probability that the message contains free. 0.12 0.152 0.60
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