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Suppose that the piecewise function f is defined by x + 3, f(x) = { -4x²+x+7, Determine which of the following statements are true. Select the correct answer below: f(x) is not continuous at x = 1 because it is not defined at x 1. O O x < 1 x > 1° = f(1) exists, but f(x) is not continuous at x = 1 because lim f(x) does not exist. x→1 ƒ(1) and lim f(x) both exist, but f(x) is x→1 O not continuous at x = 1 because lim f(x) = f(1). x-1 O f(x) is continuous at a = 1.

Suppose that the piecewise function f is defined by x + 3, f(x) = { -4x²+x+7, Determine which of the following statements are true. Select the correct answer below: f(x) is not continuous at x = 1 because it is not defined at x 1. O O x < 1 x > 1° = f(1) exists, but f(x) is not continuous at x = 1 because lim f(x) does not exist. x→1 ƒ(1) and lim f(x) both exist, but f(x) is x→1 O not continuous at x = 1 because lim f(x) = f(1). x-1 O f(x) is continuous at a = 1.

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter3: The Derivative
Section3.CR: Chapter 3 Review
Problem 4CR
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Suppose that the piecewise function f is defined by f(x) O = O x + 3, −4x²+x+7, Determine which of the following statements are true. Select the correct answer below: - f(x) is not continuous at a it is not defined at x 1. f(1) exists, but f(x) is not continuous at X = 1 because lim f(x) does not exist. x→1 x < x > 1* - 1 because f(1) and lim f(x) both exist, but f(x) is x →1 O not continuous at x = 1 because lim ƒ(x) ‡ ƒ(1). x→1 Of(x) is continuous at x = 1.
Transcribed Image Text:Suppose that the piecewise function f is defined by f(x) O = O x + 3, −4x²+x+7, Determine which of the following statements are true. Select the correct answer below: - f(x) is not continuous at a it is not defined at x 1. f(1) exists, but f(x) is not continuous at X = 1 because lim f(x) does not exist. x→1 x < x > 1* - 1 because f(1) and lim f(x) both exist, but f(x) is x →1 O not continuous at x = 1 because lim ƒ(x) ‡ ƒ(1). x→1 Of(x) is continuous at x = 1.
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