Suppose that we define the function f as follows: f(x)=√2x + 5 whenever x is not equal to 10 and f(10) = 20. It is clear that the limit of f(x), as x approaches 10, is 5. Let = 0.01 . In other words, in this problem we are given that epsilon is 0.01. Find the maximum allowable numerical value of d that satisfies the following: If x is in the interval (10-d, 10+d) and x is not equal to 10, then f(x) will be in the interval (5-0.01, 5 +0.01). Type the exact answer as a decimal in the answer box below. The maximum allowable numerical value for d is:

College Algebra (MindTap Course List)
12th Edition
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Author:R. David Gustafson, Jeff Hughes
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Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
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Suppose that we define the function f as follows: f(x) = √2x + 5 whenever x is not equal to 10 and f(10) =
20. It is clear that the limit of f(x), as x approaches 10, is 5. Let = 0.01. In other words, in this problem we are
given that epsilon is 0.01. Find the maximum allowable numerical value of d that satisfies the following:
If x is in the interval (10-d, 10+d) and x is not equal to 10, then f(x) will be in the interval (5-0.01, 5 +0.01).
Type the exact answer as a decimal in the answer box below.
The maximum allowable numerical value for d is:
Transcribed Image Text:Suppose that we define the function f as follows: f(x) = √2x + 5 whenever x is not equal to 10 and f(10) = 20. It is clear that the limit of f(x), as x approaches 10, is 5. Let = 0.01. In other words, in this problem we are given that epsilon is 0.01. Find the maximum allowable numerical value of d that satisfies the following: If x is in the interval (10-d, 10+d) and x is not equal to 10, then f(x) will be in the interval (5-0.01, 5 +0.01). Type the exact answer as a decimal in the answer box below. The maximum allowable numerical value for d is:
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