Asked Oct 16, 2019

Suppose the fluid in a woman's stomach suffering from digestion can be considered 200ml of 0.078M solution. What mass of nahco3 would she need to ingest to neutralize this much hcl


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1 mole of hydrochloric acid reacts with 1 mole sod...


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The neutralization reaction is given below, NaCI (aq)+ H,0 (1)+ СО,(g) HС(аq) + NaHсо, (аq) —> Therefore, the number of moles of hydrochloric acid is calculated as follows, Moles of HCl=Molarity x Volume Moles of HCl 0.078 x 0.2L = 0.0135 moles Moles of HCl 0.0156 moles


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