Suppose the same masses are used for a force table experiment as were used in Part 1, but each pulley is moved 1800 so that the 0.100 kg mass acts at 2000, and the 0.200 kg mass acts at 2700. What is the magnitude of the resultant in this case? How does it compare to the resultant in Part 1? SEE IMAGES FOR DETAILS

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Chapter2: Vectors
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Suppose the same masses are used for a force table experiment as were used in Part 1, but each pulley is moved 1800 so that the 0.100 kg mass acts at 2000, and the 0.200 kg mass acts at 2700. What is the magnitude of the resultant in this case? How does it compare to the resultant in Part 1?

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Experiment 2
FORCE TABLE AND VECTOR
ADDITION OF FORCES
Data Table 1
Force
Mass (kg) Force (N) Direction
F1
0.06
0,588
20.0°
F2
0.10
0.98
90.00
Equilibrant FE
1.372
250.0°
0.14
Resultant FRI
0.14
1.372
70.0°
Data Table 2
Force
Mass (kg) Force (N) Direction
F,
0.08
0.784
30.0°
0.10
0.98
100.00
F,
0.06
0.588
145.0°
Equilibrant Fp
0.18
1.764
270.0°
Resultant FR2
0.18
1.764
90.0°
Calculations Table 1
Graphical Solution
Force
Mass (kg) Force (N) Direction
0.06
0.588
20.0°
F2
0.10
0.98
90.0°
Resultant FRI
0.135
1.32
65.0°
Analytical Solution
Force
Mass (kg) Force (N) Direction x-component y-component
F,
0.06
0.588
20.0°
0.553
0.201
F.
0.10
0.98
90.0°
0.98
Resultant F
0.13
1.304
244.9°
R = 0.553
R = 1.181
Transcribed Image Text:Experiment 2 FORCE TABLE AND VECTOR ADDITION OF FORCES Data Table 1 Force Mass (kg) Force (N) Direction F1 0.06 0,588 20.0° F2 0.10 0.98 90.00 Equilibrant FE 1.372 250.0° 0.14 Resultant FRI 0.14 1.372 70.0° Data Table 2 Force Mass (kg) Force (N) Direction F, 0.08 0.784 30.0° 0.10 0.98 100.00 F, 0.06 0.588 145.0° Equilibrant Fp 0.18 1.764 270.0° Resultant FR2 0.18 1.764 90.0° Calculations Table 1 Graphical Solution Force Mass (kg) Force (N) Direction 0.06 0.588 20.0° F2 0.10 0.98 90.0° Resultant FRI 0.135 1.32 65.0° Analytical Solution Force Mass (kg) Force (N) Direction x-component y-component F, 0.06 0.588 20.0° 0.553 0.201 F. 0.10 0.98 90.0° 0.98 Resultant F 0.13 1.304 244.9° R = 0.553 R = 1.181
PART 1. ERROR CALCULATIONS
Percent Error magnitude Experimental compared to
Analytical
Percent Error magnitude Graphical compared to
Analytical = 1.226 %
Absolute Error in angle Experimental compared to
Analytical
Absolute Error in angle Graphical compared to
Analytical = 179.9°
Calculations Table 2
= 5.22%
= 174.9°
Graphical Solution
Force
Mass (kg) Force (N) Direction
F,
0.08
0.78
30.0°
100.0°
F2
F,
0.10
0.98
0.06
0.59
145.0°
Resultant F,
0.174
1.71
89.0°
Analytical Solution
Force
Mass (kg) Force (N) |Direction x-component y-component
F,
0.08
0.784
30.0°
0.679
0.392
F2
F,
0.10
0.980
100.0°
-0.170
0.965
0.06
0.588
145.00°
-0.482
0.337
Resultant F 0.173
269.0°
R, = 1.694
1.695
R = 0.027
PART 2. ERROR CALCULATIONS
Percent Error magnitude Experimental compared to
Analytical = 3.53%
Percent Error magnitude Graphical compared to
Analytical = 0.885%
Absolute Error in angle Experimental compared to
Analytical = 179.0degrees
Absolute Error in angle Graphical compared to
Analytical = 180 degrees
Transcribed Image Text:PART 1. ERROR CALCULATIONS Percent Error magnitude Experimental compared to Analytical Percent Error magnitude Graphical compared to Analytical = 1.226 % Absolute Error in angle Experimental compared to Analytical Absolute Error in angle Graphical compared to Analytical = 179.9° Calculations Table 2 = 5.22% = 174.9° Graphical Solution Force Mass (kg) Force (N) Direction F, 0.08 0.78 30.0° 100.0° F2 F, 0.10 0.98 0.06 0.59 145.0° Resultant F, 0.174 1.71 89.0° Analytical Solution Force Mass (kg) Force (N) |Direction x-component y-component F, 0.08 0.784 30.0° 0.679 0.392 F2 F, 0.10 0.980 100.0° -0.170 0.965 0.06 0.588 145.00° -0.482 0.337 Resultant F 0.173 269.0° R, = 1.694 1.695 R = 0.027 PART 2. ERROR CALCULATIONS Percent Error magnitude Experimental compared to Analytical = 3.53% Percent Error magnitude Graphical compared to Analytical = 0.885% Absolute Error in angle Experimental compared to Analytical = 179.0degrees Absolute Error in angle Graphical compared to Analytical = 180 degrees
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