Suppose we have four sets with sizes 50, 60, 70 and 80. Each pair of sets has five common elements and each triple of sets has one common element and there are no elements common to all four sets how many elements are in the union of these four sets?
Suppose we have four sets with sizes 50, 60, 70 and 80. Each pair of sets has five common elements and each triple of sets has one common element and there are no elements common to all four sets how many elements are in the union of these four sets?
Chapter9: Sequences, Probability And Counting Theory
Section9.5: Counting Principles
Problem 36SE: The number of 5-element subsets from a set containing n elements is equal to the number of 6-element...
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Suppose we have four sets with sizes 50, 60, 70 and 80. Each pair of sets has five common elements and each triple of sets has one common element and there are no elements common to all four sets how many elements are in the union of these four sets?
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