Suppose we know that at a University XYZ that 15% of students receive an A in their introductory statistics class, 20% receive a B, 30% receive a C, 10% receive a D, and the rest receive an F. For comparison, a sample of 250 students at University ABC is taken and 20% received an A, 25% received a B, 25% received a C, 10% received a D, and the remaining students failed the class. When testing (at the 5% level of significance) whether the proportions between the two universities are different, what is the critical value? (please round your answer to 3 decimal places)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 27PPS
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Suppose we know that at a University XYZ that 15% of students receive an A in their introductory statistics class, 20% receive a B, 30% receive a C, 10% receive a D, and the rest receive an F. For comparison, a sample of 250 students at University ABC is taken and 20% received an A, 25% received a B, 25% received a C, 10% received a D, and the remaining students failed the class. When testing (at the 5% level of significance) whether the proportions between the two universities are different, what is the critical value? (please round your answer to 3 decimal places)
Expert Solution
Step 1

Given Information:

University XYZ:

15% received A, 20% received B, 30% received C, 10% received D and the rest have failed.

Suppose university XYZ has 100 students in total. Then,

The number of students who received A is 15100×100=15

The number of students who received B is 20100×100=20

Similarly, the number of students who received C is 30.

The number of students who received D is 10.

The number of students who failed is 100-15+20+30+10=25.

University ABC:

20% received A, 25% received B, 25% received C, 10% received D and the remaining failed.

The sample size is 250.

So, the number of students who received A is 20100×250=50

The number of students who received B is 25100×250=62.5

The number of students who received C is 25100×250=62.5.

The number of students who received D is 10100×250=25.

The number of students who failed is 250-50+62.5+62.5+25=50.

The contingency table with observed frequencies is given below:

University/Grade A B C D F Total
XYZ 15 20 30 10 25 100
ABC 50 62.5 62.5 25 50 250
Total 65 82.5 92.5 35 75 350

 

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