Suppose you are using data on two non-negative variables Y and X to calculate Cov(Y, X). After calculating the covariance, you find out that the person entering the data accidentally divided all the values of X by 2 (that is, the person entered X/2 instead of X). If you recalculate the covariance after correcting the data, the absolute value of the corrected covariance will be the absolute value of the uncorrected covariance a. smaller than b. equal to c. larger than

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 93E
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(#8 please explain step-by-Step. It's better to give an example and do not give solution in image format thanku)

Suppose you are using data on two non-negative variables Y and X to calculate Cov(Y, X).
After calculating the covariance, you find out that the person entering the data accidentally divided
all the values of X by 2 (that is, the person entered X/2 instead of X). If you recalculate the
covariance after correcting the data, the absolute value of the corrected covariance will be
the absolute value of the uncorrected covariance
a. smaller than,
b. equal to
c. larger than
Transcribed Image Text:Suppose you are using data on two non-negative variables Y and X to calculate Cov(Y, X). After calculating the covariance, you find out that the person entering the data accidentally divided all the values of X by 2 (that is, the person entered X/2 instead of X). If you recalculate the covariance after correcting the data, the absolute value of the corrected covariance will be the absolute value of the uncorrected covariance a. smaller than, b. equal to c. larger than
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