Suppose you have a 150-kg wooden crate resting on a wood floor. The coefficients of static and kinetic friction here are μs=0.5 and μk=0.3.m = 150 kga.) What maximum force, in newtons, can you exert horizontally on the crate without moving it?b.)  If you continue to exert this force once the crate starts to slip, what will its acceleration be, in meters per square second?

Question
Asked Oct 13, 2019

Suppose you have a 150-kg wooden crate resting on a wood floor. The coefficients of static and kinetic friction here are μs=0.5 and μk=0.3.

m = 150 kg

a.) What maximum force, in newtons, can you exert horizontally on the crate without moving it?

b.)  If you continue to exert this force once the crate starts to slip, what will its acceleration be, in meters per square second?

 

check_circleExpert Solution
Step 1

(a)

The max frictional force exerted horizontally on the crate and the floor is,

Substitute the values,

F, - дЕ
3Dдтg
к, - (o5)(5okg) (9.80mha?)
-735N
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F, - дЕ 3Dдтg к, - (o5)(5okg) (9.80mha?) -735N

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Step 2

(b)

The dynamic friction of the force exerted on the crate is,

Substitute the values,

mg
F(03)(150kg)(9.80m/s)
-441N
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mg F(03)(150kg)(9.80m/s) -441N

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Step 3

The acceleration due to dynamic friction is given by,

Substitute the values, to find the acceleration of the carts slips,

...
та - F, - F
F-F
а-
т
735N-441N
а-
150kg
-196ш/s
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та - F, - F F-F а- т 735N-441N а- 150kg -196ш/s

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