Suppose you have the following list of values, which of the following searching algorithm is faster to find the value 20. -2 9 20 37 40 57 65 81 92 123 430 O Sequential Search OBinary Search O Both are the same
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- given ASCIIOFSET .FILL x0030 NegASCIIOFSET .FILL xFFD0 ASCIINewline .FILL x000d ; Newline ascii code ASCIISpace .FILL x0020 ; Space ascii code ASCIIComma .FILL x002C ; Comma ascii code Use LC-3 I/O device to print number, commas, and spaces in printCommaSpace subroutine, also check code to see if it follows instructions and modify accordinglyU={A,B,C,D,E,F}, A={A,B,D,E}, B={B,C,E,F}, and C={A,B,C,D} complete the following set operations: 1(A'n B) uC' 2. A n (Bu C;)R7.4Explain the mistakes in the following code. Not all lines contain mistakes. Each line depends on the lines preceding it. 1 double a = 1000; 2 double* p = a; 3 int* p = &a; 4 double* q; 5 *q = 2000; 6 int* r = nullptr; 7 *r = 3000;
- Can you fix this please? with 5 53 5099 1223 567 17 4 1871 8069 3581 6841 #include <iostream>using namespace std; const int SORT_MAX_SIZE = 8; bool IsPrimeRecur(int dividend, int divisor) { if (divisor == 1) { return true; } if (dividend % divisor == 0) { return false; } return IsPrimeRecur(dividend, divisor-1);} bool IsArrayPrimeRecur(int arr[], int size, int index) { cout << "Entering IsArrayPrimeRecur" << endl; if (index == size) { cout << "Leaving IsArrayPrimeRecur" << endl; return true; } if (!IsPrimeRecur(arr[index], arr[index]-1)) { cout << "Leaving IsArrayPrimeRecur" << endl; return false; } return IsArrayPrimeRecur(arr, size, index+1);} bool IsArrayPrimeIter(int arr[], int size) { cout << "Entering IsArrayPrimeIter" << endl; for (int i = 0; i < size; i++) { for (int j = 2; j < arr[i]; j++) { if (arr[i] % j == 0) {…// Task 2 // For this function, you must build a string that when printed,// will output the entire binary representation of the integer x,// no matter how many bits an integer is. You may NOT use// division (/) or mod (%) anywhere in your code, and should// instead rely on bitwise operations to read the underlying binary// representation of x.stringbuilder get_bin_1(int x) { stringbuilder sb = new_sb(); sb_append(sb, '$'); return sb;}Trace the following Code and then print the output. msg db 'hello world$' newline db 10,13,'$' buffer db 10 dup mov ah,9 mov dx,offset msg int 21h ;new line mov ah,9 mov dx, offset newline int 21h ;enter a string from the keyboard lea dx,buffer mov ah,0ah int 21h ;new line mov ah,9 mov dx,offset newline int 21h ;adding the $ symbol at the end of the string mov bx,0 mov bl,buffer[1] mov buffer[bx+2],'$' mov ah,9 mov dx,offset buffer+2 int 21h
- python: Open the file mbox-short.txt and read it line by line. When you find a line that starts with 'From ' like the following line:From stephen.marquard@uct.ac.za Sat Jan 5 09:14:16 2008 You will parse the From line using split() and print out the second word in the line (i.e. the entire address of the person who sent the message). Then print out a count at the end. Hint: make sure not to include the lines that start with 'From:'. Also look at the last line of the sample output to see how to print the count. You can download the sample data at http://www.py4e.com/code3/mbox-short.txt my code: fname = input("Enter file name: ")if len(fname) < 1: fname = "mbox-short.txt" fh = open(fname)count = 0 print("There were", count, "lines in the file with From as the first word")This is a caesar encryption code, please help me with a code to reverse this operation (decrept it) in C++ string encrypt(string text, int s){ string result = ""; // traverse text for (int i=0;i<text.length();i++) { // apply transformation to each character // Encrypt Uppercase letters if (isupper(text[i])) result += char(int(text[i]+s-65)%26 +65); // Encrypt Lowercase letters else result += char(int(text[i]+s-97)%26 +97); } // Return the resulting string return result;} int main(){ string text; int s; cin>> text; cin >> s; cout << "Text : " << text; cout << "\nShift: " << s; cout << "\nCipher: " << encrypt(text, s); return 0;}The error is in line 52. It should be ( update line 52 with ) if ( exchangeCards == "Y" || exchangeCards == "y" )" This is the answer you gave me the last time. I need line 62! The answer you are giving me over and over again doesn't make sense and it's the same code that doesn't compile! Main.cpp #include <iostream>#include <string>#include <fstream>#include <iomanip>#include <sstream>#include "card.h"#include "deck.h"#include "hand.h"using namespace std;int main(){string repeat = "Y";Deck myDeck;Hand myHand;string exchangeCards;while (repeat == "Y" || repeat == "y"){cout << endl;myHand.newHand(myDeck);myHand.print();cout << endl;cout << "Would you like to exchange any cards? [Y / N]: ";getline(cin, exchangeCards);while (exchangeCards != "Y" && exchangeCards != "y" && exchangeCards != "X" && exchangeCards != "n"){cout << "Please enter Y or N only: ";getline(cin, exchangeCards);}if(exchangeCards == "Y"…
- Consider the following code: int main() { char *s = strdup("This is a test"); char *d = " "; while (s) { char *token = strsep(&s, d); puts(token); } free(s); return 0;} Which of the following causes an error or segmentation fault? A. free is called on a pointer that was not malloc'ed B. strsep must be called with s instead of &s C. The while loop is an infinite loop D. The string s points to is in read-only memory E. Something elseJAVA HELP Ask the user for an account balance. Show, in descending order, all the accounts that have a balance greater than what the user input. Each entry is int, string, long, double, boolean (name length, name, credit card number, balance, cashback). can an expert help use string and char (instead of byte) to display the required info from a binary file Enter a balance\n9000ENTERAccounts with a balance of at least $9000.00 (sorted by balance)\n Name Account Number Balance Cash Back\n Brand Hallam 3573877643495486 9985.21 No\n Paco Verty 4508271490627227 9890.51 No\n Stanislaw Dhenin 4405942746261912 9869.27 No\nEachelle Balderstone 30526110612015 9866.30 No\n Reube Worsnop 3551244602153760 9409.97 Yes\n Tiphanie Oland 5100172198301454 9315.15 No\n Jordan Rylstone 201715141501700 9135.90 Yes\n7 results\n i have this code so far import…/* segvhunt.cFind and eliminate all code that generates Segmentation Fault*/#include <stdio.h>int main() {char **s;char foo[] = "Hello World";*s = foo;printf("s is %s\n",s);s[0] = foo;printf("s[0] is %s\n",s[0]);return(0);}