U={A,B,C,D,E,F}, A={A,B,D,E}, B={B,C,E,F}, and C={A,B,C,D} complete the following set operations: 1(A'n B) uC' 2. A n (Bu C;)
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U={A,B,C,D,E,F}, A={A,B,D,E}, B={B,C,E,F}, and C={A,B,C,D}
complete the following set operations:
1(A'n B) uC'
2. A n (Bu C;)
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- # Initialize sets A and BA = { 'a', 'b', 'c', 'd', 'e', 'f' }B = { 'c', 'd', 'f', 'h', 'j', 'k' } print('A = ', sorted(A))print('B = ',sorted(B))print(' ') AsymdiffB = set()# put your code here to compute the symmetric difference of A and B# first add all the elements that are in A but not B# then add all the elements that are in B but not A print('Symmetric Difference of A and B = ', sorted(AsymdiffB))(a,b} u {} = {a,b} True False The order of the elements in a set is important True False The empty set is a subset of every other set True FalseCreate a spyder(anaconda) program that will ask the user to enter 2 non-empty set and display their intersection and union. Design the following function in the program: set_intersection-this function gets the intersection of 2 given sets set_union-this function gets the union of two given sets
- 1. Create an empty set1 and add the following elements: rice, bread, tea, milk, biscuits. b) Create another set2 with the elements: sweets, wheat, rice, tea, corn, millets c) Find the union of set1 and set2Count dominators def count_dominators(items): An element of items is said to be a dominator if every element to its right (not just the one element that is immediately to its right) is strictly smaller than it. By this definition, the last item of the list is automatically a dominator. This function should count how many elements in items are dominators, and return that count. For example, dominators of [42, 7, 12, 9, 13, 5] would be the elements 42, 13 and 5. Before starting to write code for this function, you should consult the parable of "Shlemiel the painter" and think how this seemingly silly tale from a simpler time relates to today's computational problems performed on lists, strings and other sequences. This problem will be the first of many that you will encounter during and after this course to illustrate the important principle of using only one loop to achieve in a tiny fraction of time the same end result that Shlemiel achieves with two nested loops. Your workload…Relational Thinking sets 25 students attend a programming workshop. 15 students study Python. 14 students study Java. 5 students changed to another field of study. How many students study both Java and Python. Use set diagrams to explain your answer. Draw the diagram showing the relationship A ⊆ B Draw the diagram to show the relationship A ∩ B Let E be the set of even numbers, and let P be the set of prime numbers. Use set notation to express the following statement: “2 is the only even prime number.” List the set operations most closely matching disjunction, conjunction, negation, conditional (if then), biconditional (iff if and only if)
- #ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…Write a display function and delete function in the following code: Declare the libraries Declare the struct Node void create (int A[], int n) { int i; struct Node *t, *last; first = (struct Node *)malloc(sizeof(struct Node)); first->data=A[0]; first->next=NULL; last=first; for(i=1;i<n;i++) { t=(struct Node *)malloc(sizeof(struct Node)); t->data=A[i]; t->next=NULL; last->next=t; last=t; } } Write the Delete Function Write the display function int main() { int A[]={10,20,30,40,50}; create(A,5); Delete(first,4); Display(first); return 0; }6.2 Create a Product class with Product Id & Product Name. Write a program to accept information of 10 products and store that in HashSet. Do following operations, a.Search a particular product in the HashSet.b.Remove a particular product from the HashSet by using product id.(Referbelow table for the product list) Product Id Product Name P001 Maruti 800 P002 Maruti Zen P003 Maruti Dezire P004 Maruti Alto
- (C Language) The Fibonacci sequence begins with 0 and then 1 follows. All subsequent values are the sum of the previous two, for example: 0, 1, 1, 2, 3, 5, 8, 13. Complete the Fibonacci() function, which takes in an index, n, and returns the nth value in the sequence. Any negative index values should return -1.1. Consider the below code snippet. Assume bool foundPair and int pairCount are both declared and have valid values. if (foundPair) cout << "We have a pair!\n"; pairCount++; True/False: when we run this code, pairCount will only increment if foundPair is true. A) True B) False(Duplicate Elimination) Write a program that reads in a series of first names and eliminates duplicates by storing them in a Set. Allow the user to search for a first name. Add a name to set, use end to terminate input: Search a name, use end to terminate searching: Sample output as follows: