(Suppose you need to design a tension test machine capable of testing specimens that have nominal ultimate stresses as high as σu = 100 ksi . How much force must the machine be capable of generating? Assume the testing specimen has the ASTM shape shown. Answer for this is 19.6 kip)(If the maximum nominal strain is ϵf = 0.7 just before the test specimen fractures and the test machine operates by moving only one grip, how far must that grip be designed to travel? The total length of the deforming part of the specimen is 3 in. Answer for this is 2.10 in)Do not know if this info is needed but this was the other 2 parts Force (kip)141210842042.00stress =strain =2.20ksi2.40Length (in)stress =strain =2.602.80ksistress =strain =ksi ●Question 1.png72°FSunny|DW:d₂ = 0.5 in.L₁= 2 in.HoQ Search+100%00▬▬0XWQuestion 12.pngH@IA⠀TQYou have built the majority of the tension testing machine, but much of the instrumentation is still being assembled. To test the machine, you perform a test on a steel specimen with known properties. The machine provides you withthe given load data, and you manually record the lengths between the marks on the specimen at each point using an extensometer to obtain the table of data shown below.L (in)2.00122.00252.03502.07982.13132.19372.28043.517.097.879.8410.802.477412.378.8311.77P (kip)Use these results to calculate the stress and strain at the yield point, the ultimate strength point, and the fracture point.57%2.579111.80<2.665710.8104) O2.72819.8110:53 AM10/6/20232.74979.42

Given data:Ultimate stress, σu = 100 ksidiameter of the specimen, d = 0.5 in (from the given…

Answered: (Suppose you need to design a tension…

Elements Of Electromagnetics

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ISBN:9780190698614

Author:Sadiku, Matthew N. O.

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(Suppose you need to design a tension test machine capable of testing specimens that have nominal ultimate stresses as high as σu = 100 ksi . How much force must the machine be capable of generating? Assume the testing specimen has the ASTM shape shown. Answer for this is 19.6 kip)

(If the maximum nominal strain is ϵf = 0.7 just before the test specimen fractures and the test machine operates by moving only one grip, how far must that grip be designed to travel? The total length of the deforming part of the specimen is 3 in. Answer for this is 2.10 in)

Do not know if this info is needed but this was the other 2 parts

Force (kip)
14
12
10
8
4
2
04
2.00
stress =
strain =
2.20
ksi
2.40
Length (in)
stress =
strain =
2.60
2.80
ksi
stress =
strain =
ksi

●
Question 1.png
72°F
Sunny
|
D
W
:
d₂ = 0.5 in.
L₁= 2 in.
H
o
Q Search
+
100%
00
▬▬
0
X
W
Question 12.png
H
@
IA
⠀
T
Q
You have built the majority of the tension testing machine, but much of the instrumentation is still being assembled. To test the machine, you perform a test on a steel specimen with known properties. The machine provides you with
the given load data, and you manually record the lengths between the marks on the specimen at each point using an extensometer to obtain the table of data shown below.
L (in)
2.0012
2.0025
2.0350
2.0798
2.1313
2.1937
2.2804
3.51
7.09
7.87
9.84
10.80
2.4774
12.37
8.83
11.77
P (kip)
Use these results to calculate the stress and strain at the yield point, the ultimate strength point, and the fracture point.
57%
2.5791
11.80
<
2.6657
10.81
0
4) O
2.7281
9.81
10:53 AM
10/6/2023
2.7497
9.42

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