Need help, please. Suppose you want to test the results of a transformation by growing E. coli cells in LB medium containing ampicillin as the antibiotic for selection. Ampicillin at aconcentration of 100 µg/mL will kill cells that do not contain an ampicillin resistance gene, but will allow the growth of cells that have been transformed with this gene.The concentrated stock of ampicillin is 100 mg/mL. How many microliters of the ampicillin stock should you add to 250 mL of LB for a bacterial culture?ATPase proteins hydrolyze ATP to ADP + Pi. In order to check the ATPase activity of a chaperone, one can perform an ATPase assay. The assay is performed in a tube with a200 µL total reaction volume, containing ATP at a concentration of 2 mM. The stock solution of ATP is 150 mM in buffer. What volume of the stock solution do you need to addto the reaction mixture to make it 2 mM ATP?How much ATP (in solid form) do you need to weigh, in order to make 1.5 mL of a stock solution which has a concentration of 150 mM ATP? The molecular weight of ATP is551.14 (according to the label on the bottle of powder you found on the chemical shelf).

Equation of dilution: M1V1 = M2V2where: M1 is the molar concentration of the stock solution. M2 is…

Answered: Suppose you want to test the results of…

Biology Today and Tomorrow without Physiology (MindTap Course List)

5th Edition

ISBN:9781305117396

Author:Cecie Starr, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Christine Evers, Lisa Starr

Chapter10: Biotechnology

Section: Chapter Questions

Problem 1CT

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A student mixes some heat-killed type IIS Streptococcus pneumoniae bacteria with live type IIR bacteria and injects the mixture into a mouse. The mouse develops pneumonia and dies. The student recovers some type IIS bacteria from the dead mouse. If this is the only experiment conducted by the student, has the student demonstrated that transformation has taken place? What other explanations might explain the presence of the type IIS bacteria in the dead mouse?
Cold sensitive mutation (Cs) results in a mutant phenotype below a particular temperature. Bacteria with mutation ess-2 (Ts) can form colonies at 32oC but not at 37oC and 42oC, while bacteria with mutation ess-5 (Cs) can form colonies at 42oC but not at 32oC and 37oC. What would be the phenotype of an ess-2 (Ts) and ess-5 (Cs) double mutant?
If Avery, Macleod, and McCarty had observed transformation after removing DNA and RNA, but NOT after removing proteins, they would have concluded that _______. Group of answer choices A polysaccharide is the genetic material in Streptococcus pneumoniae RNA is the genetic material in Streptococcus pneumoniae The genetic material in Streptococcus pneumoniae is a protein Mice with diets rich in proteins are resistant to Streptococcus pneumoniae infection The preparations were contaminated
We isolate DNA from a bacteria that is wild type for the genes arg leu and his shear it in a blender mix it into a culture of bacteria that is mutant for the genes arg leu and his . We then plate on various media. These are the results: Media with arginine 20 colonies /ml Media with histidine 300 colonies /ml Media with leucine 500 colonies /ml Media with all three 10000 colonies/ml 21. What is this experiment called? A. transpiration B. conjugation C. transformation D. transduction
Production of a recombinant protein by E. coli is proportional to cell growth. Ammonia is used as a source of N and glucose as a source of C, under aerobic conditions. The recombinant protein has a general formula CH1.55N0.31O0.25 and the cell CH1.77N0.4900.24. The yield of biomass from glucose is 0.48 gcel/gglic, and the yield of recombinant protein from glucose is about 20% of that for biomass.a) How much ammonia is needed to produce 50 g of cells producing the recombinant protein?b) What is the oxygen demand in this process?c) For the cultivation of a wild E. coli not producing the recombinant protein, how different would the ammonia and oxygen demand be if the biomass yield remained at 0.48 gcel/gglyc ?
A bacterial transformation is performed with a donor strain that is resistant to four drugs, A, B, C, and D, and a recipient strain that is sensitive to all four drugs. The resulting recipient cell population is divided and plated onmedia containing various combinations of the drugs. The following table shows the results.a. One of the genes is distant from the other three, which appear to be closely linked. Which is the distant gene? b. What is the likely order of the three closely linked genes
For a molecular cloning experiment using the bacterial strain E. coli K12 is used to insert the gene rspL with pUC19. The first attempt utilized the restriction enzyme BamHI which did not produce any transformations. The second attempt utilized the restriction enzymes BamHI and EcoRI. Why was BamHI used first and what difference did the EcoRI do?
One experiment that showed the DNA carried genetic information was the "Transformation" experiment by Avery, McCarty, and MacLeod where they injected mice with non-pathogenetic bacteria that had been incubated in the remains of pathogenic bacteria. What did they find when they incubated non-pathogenic bacteria in just the protein from the pathogenic bacteria? In this case there was no transformation They found that the non-pathogenic bacteria were transformed into pathogenic bacteria In this case the mice were sickened but did not die They found that some of the protein could cause transformation but other proteins could not
Recombinant protein production by a genetically modified Escherichia coli strain is proportional to cell growth. Ammonia is used as a nitrogen source for aerobic glucose respiration. The recombinant protein has the general formula CH1,55O0,31N0,25, while that of the cellular biomass is CH1,77O0,49N0,24. The biomass yield from glucose equals 0.50 g/g, while the recombinant protein yield from glucose corresponds to 20% of the cell yield from substrate.a) How much ammonia is required? What is the oxygen demand? (b) If the biomass yield remains the same, what are the ammonia and oxygen requirements for a wild-type strain of E. coli, with cell biomass of the same elemental composition, but unable to synthesize the recombinant protein? (c) On an industrial scale, cultivation takes place in a continuous fermenter at 28°C and the desired recombinant protein production rate is 7 g/h. Since the viscosity of the culture broth is considerable, the energy input due to agitation cannot be neglected.…
In a cotransformation experiment DNA was isolated from a donor strain that was proA+ and strC+ and sensitive to tetracycline. (The proA and strC genes confer the ability to synthesize proline and confer streptomycin resistance, respectively.) A recipient strain is proA− and strC− and isresistant to tetracycline. After transformation, the bacteria werefirst streaked on a medium containing proline, streptomycin, andtetracycline. Colonies were then restreaked on a medium containingstreptomycin and tetracycline. (Note: Each type of medium hadcarbon and nitrogen sources for growth.) The following resultswere obtained:70 colonies grew on the medium containing proline, streptomycin,and tetracycline, but only 2 of these 70 colonies grew whenrestreaked on the medium containing streptomycin and tetracyclinebut lacking proline.What would you expect the cotransformation frequency to be ifthe average size of the DNA fragments was 4 minutes and thetwo genes were 1.4 minutes apart?
Which of the following would best ensure that a kidney cell and a liver cell from the same person would express different genes? Group of answer choices differences in introns unique sets of transcription factors they only have specific genes unique sets of promoters 2. Refer to the metabolic pathway illustrated. If A, B, and C are all required for growth, a strain mutant for the gene encoding enzyme A would be able to grow on medium supplemented with which of the following nutrient(s)?
To maximize the number of mutations following UV irradiation, should you incubate the irradiated cells in the light or in the dark, or does it make any difference? Explain your answer.

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