Answered: Suppose you wish to calculate the…

Suppose you wish to calculate the acceleration of gravity on the surface of a distant planet. What properties of the planet must you know? Justify your answer.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter7: Gravity

Section: Chapter Questions

Problem 25PQ

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Suppose you wish to calculate the acceleration of gravity on the surface of a distant planet. What properties of the planet must you know? Justify your answer.Suppose you wish to calculate the acceleration of gravity on the surface of a distant planet. What properties of the planet must you know? Justify your answer.

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How do you determine the mass of a planet with just its distance to another object, and the gravitational field intensity?
. With the mass of earth as 5.9722×10 to the 24 kg. and the mass of the moon is 7.38 x10 to the 22kg.with a distance of 384790km a. what is the gravitational pull between the two objects? b. what happens to gravitational pull if you reduced the distance into 1/2?
When you travel to another part of the solar system (Jupiter, Mars, etc) what changes, your mass or your weight? Explain why.
6.) Planet X has 10 times the mass of the Earth’s mass. The star that it orbits has the same mass as our Sun.The planet average distance from its star is 2.5826 (10)11 ??.a) What is the gravitational force between Planet X and its star in units of Newtons?b) What is the velocity of Planet X as it orbits its star in units of metres per second?
1. using Newton’s Law of Universal Gravitation and some kinematics calculation we can calculate the mass of the planet. For this, use this equation below: ?planet =(9.340×1024)×(vmax)×(Pstar)1/3×(Mstar)2/3 Given: - vmax = 1.5 m/s - Pstar = 3.5 days - Mstar = 1.148 Msun, where Msun = 1.98847×1030 kg. This calculation is not shown.
Please prove the relationship between gravity and universal gravitation on Earth , and use the expression to explain in detail . (I've been obsessed with this problem all day, and I'm really sick.)
The acceleration of gravity at the surface of a planet of radius 6,106 km is 10.7 m/s2. What is the acceleration of gravity, in m/s2, at 295 km from the planet's surface?
We sent a probe out to orbit the planet Kerbal at a distance of 5.5x107m from the middle of the planet. It took our probe 3.5x105s to orbit the planet. Which equation will be used to calculate the mass of planet Kerbal? Possible Formulas that can be used to answer the question: v=(2πr)/T ac=v2/r ac=(4π2r)/T2 Fc=mac Fg=mg F=(Gm1m2)/d2 g=Gm/r2 T2=(4π2/Gm)r3 v=√(Gm)/r g=9.80m/s2 G=6.67x10-11 (N∙m2)/kg2
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An extrasolar planet has a mass of eight times that of the Earth and radius of twice that of the Earth? What is the escape velocity of the planet if the escape velocity of the Earth is 11.2 km/sec? An object with a mass of 100 kg measured on Earth is taken to the Mars. What is the mass of the object on the Mars’s surface if the acceleration due to gravity on Mars is two-fifth of that on Earth?
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So let's consider a person with a mass of 51.0 kg standing on the Earth. To find the gravitational force on the person, we'll again use Newton's law of universal gravitation with the Earth as m2 and the radius of the Earth for the distance F = GmME RE2 . Now all we need to do is substitute values and calculate. We already said m = 51.0 kg, and we know G = 6.67 ✕ 10−11 N · m2/kg2. The Earth is not a perfect sphere, but, its average radius is RE = 6.37 ✕ 106 m. The mass of the Earth is ME = 5.97 ✕ 10−24 kg. We can then substitute these values in the following formula. (Enter your answer in N.) F = (6.67 ✕ 10−11 N · m2/kg2)(51.0 kg)(5.97 ✕ 1024 kg) (6.37 ✕ 106 m)2 (A) = _______ N Now let's compare this result to the person's weight (in N) found by multiplying the person's mass by g (or, that is, w = mg) where g = 9.80 m/s2. w = (51.0 kg)(9.80 m/s2) =(b) __________________ N You should have found that these two methods give about the same result!…