Suppose f(x)=x4+3x+1f(x)=x4+3x+1. In this problem, we will show that ff has exactly one root (or zero) in the interval [−5,−1][−5,−1]. (a) First, we show that ff has a root in the interval (−5,−1)(−5,−1). Since ff is a ____ function on the interval [−5,−1][−5,−1] and f(−5)=f(−5)=  and f(−1)=f(−1)=  , the graph of y=f(x)y=f(x) must cross the xx-axis at some point in the interval (−5,−1)(−5,−1) by the _____ . Thus, ff has at least one root in the interval [−5,−1][−5,−1]. (b) Second, we show that ff cannot have more than one root in the interval [−5,−1][−5,−1] by a thought experiment. Suppose that there were two roots x=ax=a and x=bx=b in the interval [−5,−1][−5,−1] with a

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.5: Rational Functions
Problem 54E
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 Suppose f(x)=x4+3x+1f(x)=x4+3x+1. In this problem, we will show that ff has exactly one root (or zero) in the interval [−5,−1][−5,−1].

(a) First, we show that ff has a root in the interval (−5,−1)(−5,−1). Since ff is a ____ function on the interval [−5,−1][−5,−1] and f(−5)=f(−5)=  and f(−1)=f(−1)=  , the graph of y=f(x)y=f(x) must cross the xx-axis at some point in the interval (−5,−1)(−5,−1) by the _____ . Thus, ff has at least one root in the interval [−5,−1][−5,−1].

(b) Second, we show that ff cannot have more than one root in the interval [−5,−1][−5,−1] by a thought experiment. Suppose that there were two roots x=ax=a and x=bx=b in the interval [−5,−1][−5,−1] with a<ba<b. Then f(a)=f(b)=f(a)=f(b)=  . Since ff is _____on the interval [−5,−1][−5,−1] and _____on the interval (−5,−1)(−5,−1), by ______there would exist a point cc in interval (a,b)(a,b) so that f′(c)=0f′(c)=0. However, the only solution to f′(x)=0f′(x)=0 is x=x=  , which is not in the interval (a,b)(a,b), since (a,b)⊆[−5,−1](a,b)⊆[−5,−1]. Thus, ff cannot have more than one root in [−5,−1][−5,−1].

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