switches and hosts
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10.23.33.234 and MASK 255.255.255.224
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10.14.64.22 and MASK 255.255.248.0
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10.54.21.15 and MASK 255.252.0.0
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172.16.33.234 and MASK 255.255.255.224
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172.18.64.22 and MASK 255.255.248.0
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172.19.21.15 and MASK 255.255.252.0
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192.168.33.234 and MASK 255.255.255.224
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192.168.64.22 and MASK 255.255.255.248
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192.168.21.15 and MASK 255.255.255.252
Please illustrate the above using router, switches and hosts
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- ʙᴇʟᴏᴡ ɪꜱ ʜᴏᴡ ᴛʜᴇ ꜰɪʟᴇɴᴀᴍᴇꜱ ᴀʀᴇ ʀᴇᴘʀᴇꜱᴇɴᴛᴇᴅᴀʀʀᴀʏ[] = [50, 11, 33, 21, 40, 50, 40, 40, 21]ʙᴇʟᴏᴡ ɪꜱ ᴛʜᴇ ᴇxᴘᴇᴄᴛᴇᴅ ᴏᴜᴛᴘᴜᴛ ᴀꜰᴛᴇʀ ᴅᴇ-ᴅᴜᴘʟɪᴄᴀᴛɪᴏɴᴀʀʀᴀʏ[] = [11, 21, 33, 40, 50] ʏᴏᴜ ᴄᴀɴɴᴏᴛ ᴜꜱᴇ ʟɪʙʀᴀʀʏ ꜰᴜɴᴄᴛɪᴏɴꜱ ᴛᴏ ᴇɪᴛʜᴇʀꜱᴏʀᴛ ᴀɴᴅ ᴏʀ ᴘᴇʀꜰᴏʀᴍ ᴛʜᴇ ᴅᴇ-ᴅᴜᴘʟɪᴄᴀᴛɪᴏɴ ᴏᴘᴇʀᴀᴛɪᴏɴ. ɪɴ ᴊᴀᴠᴀ ɪᴍᴘʟᴇᴍᴇɴᴛ ᴛʜᴇ ꜰᴜɴᴄᴛɪᴏɴ ɪɴ ꜱᴜᴄʜ ᴀ ᴡᴀʏ ᴛʜᴀᴛ ʏᴏᴜʀ ꜱᴏʟᴜᴛɪᴏɴ ꜱᴏʟᴠᴇꜱᴛʜᴇ ᴘʀᴏʙʟᴇᴍ ᴡɪᴛʜ ᴏ(ɴ ʟᴏɢ2(ɴ)) ᴛɪᴍᴇ ᴄᴏᴍᴘʟᴇxɪᴛʏ ᴏᴠᴇʀᴀʟʟ ʙᴜᴛ ꜱᴛᴀʏꜱ ᴡɪᴛʜɪɴ ᴛʜᴇ ʙᴏᴜɴᴅꜱ ᴏꜰ ᴏ(1) ꜱᴘᴀᴄᴇ ᴄᴏᴍᴘʟᴇxɪᴛʏ. ʜᴇʀᴇ, ɴ ɪꜱ ᴛʜᴇ ʟᴇɴɢᴛʜ ᴏꜰ ᴛʜᴇ ʟɪꜱᴛ ᴏꜰɪɴᴘᴜᴛ ɪɴᴛᴇɢᴇʀꜱ (ᴀʀʀᴀʏ). ɪ ʙᴇʟɪᴇᴠᴇ ᴛʜᴇ ꜱᴏʀᴛɪɴɢ ʀᴏᴜᴛɪɴᴇ ᴛʜᴀᴛ ᴄᴀɴ ʙᴇ ᴜꜱᴇᴅ ʜᴇʀᴇ ɪꜱ Qᴜɪᴄᴋ ꜱᴏʀᴛ. ᴘʟᴇᴀꜱᴇ ꜱᴛᴀᴛᴇ ᴀꜱ ᴄᴏᴅᴇ ᴄᴏᴍᴍᴇɴᴛ ᴡʜɪᴄʜ ꜱᴏʀᴛɪɴɢ ʀᴏᴜᴛɪɴᴇ ʏᴏᴜ ᴀʀᴇ ᴜꜱɪɴɢ, ꜱᴏʀᴛ ᴛʜᴇ ᴀʀʀᴀʏ ᴡɪᴛʜ ᴛʜᴀᴛ ᴀʟɢᴏʀɪᴛʜᴍ ᴀɴᴅ ꜱᴏʟᴠᴇ ᴛʜᴇ ᴅᴇ-ᴅᴜᴘʟɪᴄᴀᴛɪᴏɴ ᴘʀᴏʙʟᴇᴍ ᴛʜᴇʀᴇᴀꜰᴛᴇʀ. ᴅᴇ-ᴅᴜᴘʟɪᴄᴀᴛɪᴏɴ ᴘᴀʀᴛ ᴏꜰ ᴛʜᴇ ꜱᴏʟᴜᴛɪᴏɴ ɪɴ ɪᴛꜱᴇʟꜰ ᴍᴜꜱᴛ ᴀᴅʜᴇʀᴇ ᴛᴏ ᴏ(ɴ) ᴛɪᴍᴇ ᴀɴᴅ ᴏ(1) ꜱᴘᴀᴄᴇ ʙᴏᴜɴᴅꜱ ᴄᴏᴍᴍᴇɴᴛ ᴇᴠᴇʀʏ ʟɪɴᴇ ᴏꜰ ᴄᴏᴅᴇᴘʟᴇᴀꜱᴇ ᴡʀɪᴛᴇ ᴛᴇꜱᴛ-ᴄᴀꜱᴇꜱ ᴏɴ ʜᴏᴡ ᴏɴᴇ ᴡᴏᴜʟᴅᴛᴇꜱᴛ ᴛʜᴇ ꜱᴏʟᴜᴛɪᴏɴ ᴀꜱꜱᴜᴍᴘᴛɪᴏɴꜱ ᴀɴᴅ ʜᴇɴᴄᴇ ᴛʜᴇ ᴄᴏᴅᴇ ᴇxᴀᴍᴘʟᴇ ᴏꜰ ᴄᴀꜱᴇꜱ ᴛᴏ ʙᴇ ᴛᴇꜱᴛᴇᴅ ꜰᴏʀ ᴀʀᴇ ʟɪᴋᴇ : ᴡʜᴀᴛ ɪꜰ ᴛʜᴇ ᴀʀʀᴀʏ ɪɴᴘᴜᴛ ᴡʜɪᴄʜɪꜱ…'list_1': [15, 20, 26, 432, 23, 34, 4, 3, 2, 15, 10, 28, 39, 56, 10, 10, 10, 432, 3, 3] 'list_2': [250, 101, 210, 150, 150 ,201, 205, 250, 143, 158, 250, 11, 101, 205] 'list_3': [350, 1000, 12, 450, 960, 966, 852, 350, 1000, 960, 852, 1200, 1000] There are 3 lists in above. These lists will be created with the specified names. You must remove the elements that is repeated in each listafter creating them. At last, calculate the averages of each list, and append the average values to each list with append function. Print eachlist. Example outputs: [1,2,3,4, 2.5] [3,6,9,12, 7.5] [3,4,8,5, 4]This is what my professor said: Items are 4 bytes, pages are 2k, so ~512 items fit on a page. Even if we start in the beginning of a page, the first access will be a miss followed by ~200 hits, then a TLB miss followed by ~500 hits, so the hit rate is ~100%5. Page size 512 means 9 bits of offset and 7 bits of VPN. The offset is just the decimal version of 1 0111 0111 [unsigned] which is 375The offset is 0011 100 which is 28. Is he correct?
- Here you will solve and break the simple code and decrypt a message. Then create your own encryption code. a) Here is the encrypted message: 27, 5, 16, 6, 5, 31, 18, 14, 34, 6, 18, 34, 27, 10, 18, 5, 31, 13, 31, 9, 18, 4, 27, 30, 31, 18, 27, 18, 4, 0, 10, 11, 27, 2, 31, 18, 34, 27, 10, 18, 5, 31, 13, 31, 9, 18, 11, 9, 0, 31, 30, 18, 27, 5, 16, 11, 34, 0, 5, 33, 18, 5, 31, 14, 21 Decoded message: _____________________________________________________________________________________________________________________ (Albert Einstein) This string of numbers represents a coded message. Each letter (based on the position in the alphabet), a space (SP), and each punctuation mark was given a number from 1 (for A) to 30 (for the explanation mark) in the first blank row of the table. Each number in the first row was then increase by 61 (add 61 to each number for the next row of the table), and this answer was converted to its congruent number modulo 35 for the last row of the table. To decode…Here you will solve and break the simple code and decrypt a message. a) Here is the encrypted message: 27, 5, 16, 6, 5, 31, 18, 14, 34, 6, 18, 34, 27, 10, 18, 5, 31, 13, 31, 9, 18, 4, 27, 30, 31, 18, 27, 18, 4, 0, 10, 11, 27, 2, 31, 18, 34, 27, 10, 18, 5, 31, 13, 31, 9, 18, 11, 9, 0, 31, 30, 18, 27, 5, 16, 11, 34, 0, 5, 33, 18, 5, 31, 14, 21 Decoded message: _____________________________________________________________________________________________________________________ (Albert Einstein) This string of numbers represents a coded message. Each letter (based on the position in the alphabet), a space (SP), and each punctuation mark was given a number from 1 (for A) to 30 (for the explanation mark) in the first blank row of the table. Each number in the first row was then increase by 61 (add 61 to each number for the next row of the table), and this answer was converted to its congruent number modulo 35 for the last row of the table. To decode the message, find the numbers in the…Consider the following page address stream: 2 1 4 3 5 3 2 4 5 2 1 2 4 3 1 Which of the following causes the most page faults to occur on a machine with 3 frames? Scheme that causes the most faults: a) First in First out b) LRU and FIFO are the same number of faults c) FIFO and Opitimal are the same number of faults d) All have the same number of faults e) Least Recently Used f) No faults occurs g) LRU and Optimal are the same number of faults h) Optimal NUMBER OF FAULTS CAUSED: a)
- Which of the following is not the resultant sequence after first run of quicksort? (A)11,5,19,1,15,26,59,61,48,37 (B)2,3,1,4,9,5,6,7,10 (C)15,8,32,4,831,52,64,41 (D)1,4,3,2,51. We assume Z26 ={0, 1, …, 25} is the alphabet for One-Time Pad, and the Plaintext space = Ciphertext space = Key space = (Z26)5. If the plaintext is (11, 8, 5, 19, 22) and the key is (2, 20, 15, 10, 6), what is the ciphertext? ( ) (13, 2, 20, 3, 2). (13, 28, 20, 29, 28). (13, 28, 20, 29, 2) (13, 24, 6, 23, 24). 2. We assume Z26 ={0, 1, …, 25} is the alphabet for One-Time Pad, and the Plaintext space = Ciphertext space = Key space = (Z26)5. If the ciphertext is (11, 24, 5, 19, 22) and the key is (2, 20, 2, 10, 23), what is the decrypted plaintext? ( ) (13, 18, 7, 3, 19). (9, 4, 7, 29, 25). (13, 18, 3, 29, 25) (9, 4, 3, 9, 25). 3. For the binary version of One-Time Pad, if the ciphertext is 10110010 and the key is 01011010, what is the corresponding plaintext? ( )2.1 Bob and Alice are classmates who are studying at university of Limpopo doing their final year studies in Computer Science.Due to the ongoing pandemic of covid 19, lectures are virtual.However they have choosen not to attend virtual class but download class recordings.Discuss the process of getting the videos to play on their media player after downloding. In your explanation include all the protocols involved.
- 11.What is the sequence of events in the life cycle of a page? 16. What is the function of a garbage collector? 17. What is caching and how does it work?A local area network requires eight characters for a password. The first character must be a letter, but the remaining seven characters can either be a letter or a digit (0 through 9). Lower & uppercase letters are considered the same. A. How many passwords are possible for the local area network? B. In 1 second, a 3-GHz computer processor can generate about 3 million passwords. How long would it take such a processor to generate all the passwords above? In seconds.10. The technique of temporarily delaying outgoing acknowledgements so that they can be hooked onto the next outgoing data frame is known as a. Bit stuffing b. Piggy backing c. Pipelining d. Broadcasting