t=0 R1 R2 AC V=150*sin(314*t - 30) V, R1=200 Ohms, R2=100 Ohms, L=0.2 H. Current IL is: Выберите один ответ: 0.489*sin(314*t - 41.81) - 0.796*exp(-1500*t) O 0.25*sin(314*t - 30) - 0.25*exp(-1500*t) O 1.27*sin(314*t - 62.11) - 0.256*exp(-1500*t) O 0.489*sin(314*t - 35.62) - 1.796*exp(-1000*t) 0.389*sin(314*t - 41.81) - 0.496*exp(-333.33*t)

t=0 R1 R2 AC V=150sin(314t - 30) V, R1=200 Ohms, R2=100 Ohms, L=0.2 H. Current IL is: Выберите один ответ: 0.489sin(314t - 41.81) - 0.796exp(-1500t) O 0.25sin(314t - 30) - 0.25exp(-1500t) O 1.27sin(314t - 62.11) - 0.256exp(-1500t) O 0.489sin(314t - 35.62) - 1.796exp(-1000t) 0.389sin(314t - 41.81) - 0.496exp(-333.33t)

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter11: Transient Stability

Section: Chapter Questions

Problem 11.6P

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