T2 = 390 K Vz = ? P, = 300 kPa = 400 K v, = 20 m/sec D1 = 15 cm P1 = ? T1 m =?
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To determine:
Given data:
Assumptions:
- Flow through the nozzle is isentropic.
- Air is the fluid.
- Air is the ideal gas
- Specific heats are constant.
Apply steady flow energy equation,
Step by step
Solved in 4 steps with 5 images
- A solid steel shaft 4.5 m long is stressed at 75 MPa when twisted through 4.5°. What power can be transmitted by the shaft at 25 Hz? Use G = 83 GPa.Given: l1=1,3l; l2=1,9l; l3=1,2l; M1=-0,6M; M2=-1,6M; M3=1,9M. Parameter of length l=40cm; cross section diameters: d=41mm; d0=26mm. The shaft is made of steel with yielding shear stress τY=250MPa; factor of safety n=1,6. Find: the allowable value of load parameter (in Nm) MA = ?A motor drives a shaft at 12 Hz and delivers 20 kW of power as shown in Fig.4. (a) If the shaft has a diameter of 30 mm, what is the maximum shear stress τmax in the shaft? (b) If the maximum allowable shear stress is 40 MPa, what is the minimum permissible diameter dmin of the shaft? A solid circular bar of diameter d = 50 mm is twisted in a testing machine until the applied torque reaches the value T = 500 Nm as shown in Fig.4. At this value of torque, a strain gage oriented at 45 ° to the axis of the bar gives a reading ε =339 ×10-6 . What is the shear modulus G of the material?
- The shaft and the flange of a marine engine are to be designed for flange coupling, in which the flange is forged on the end of the shaft. The following particulars are to be considered in the design: Power of the engine=2.4 MW Speed of the engine 80 r.p.m Permissible shear stress in bolts and shaft = 60 MPa Number of bolts used =6 Pitch circle diameter of bolts=1.6* Dimeter of shaft Find 1.diameter of shaft; 2.diameter of bolts; 3.thickness of flange; and 4.diameter of flange. (25 degreaA solid steel shaft 3 m long is stressed to 65 MPa when twisted through 3 degrees. Using G = 81 GPa, what power can be transmitted by the shaft at 125 r/s? Answer must be in kWA solid shaft 5 m long is stressed to 60 MPa when twisted through 4 deg . Using G = 83 GPa, what power (Hp) can be transmitted by the shaft at 20 rps?
- 4kN/m uniform spring load h = 2b allowable normal stress 12MPa h(min) = ?A rotating hollow shaft is to transmit 30kw at 300rpm, the maximum torque being 20% greater than the mean. The shear stress is not to exceed 60Mpa and twist in a length of 2 meters not to exceed 1.2 degrees. Find the external diameter of the shaft if the external diameter to internal diameter ratio of 2.5. Consider modulus of rigidity as 84 Gpa.A torsion dynamometer is fitted on a turbine shaft to measure the angle of twist. It is observed that the shaft twists 1.5° in a length of 5 metres at 500 r.p.m. The shaft is solid and has a diameter of 200 mm. If the modulus of rigidity for the shaft material is 85 GPa, find the power transmitted by the turbine.
- A motor (located at C) provides 50kW of power which is then used by pulleys A and B. When the motor is running, the transmission shaft (which is made of Cr-Ni steel and has a diameter of 5cm) starts rotating at a speed of 200 rpm. 1) Find the moment of force at pulleys A, B and C. 2) Find the torque in each section (between the pulleys). 3) What is the safety factor of the driveshaft on the ultimate limit?Given: l1=2l; l2=1,2l; l3=1,5l; M1=-1,7M; M2=0M; M3=1,4M. Parameter of length l=40cm; parameter of load М=410Nm. The shaft is made of steel with yielding shear stress τY=190MPa; factor of safety n=1,9. Find: the diameter (in mm) of cross section from strength calculation d = ?Mechanical design The maximum load in a rotating shaft is subjected to bending moment of 1 kN.m and a torque of 1 kN.m. The member is made of steel the Ultimate Tensile Strength 440 MPa, Yield Tensile Strength 370 MPa. With a safety factor of 4, kt = km = 1.5 and keyway stress consternation is presented. According to the maximum shear stress theory, the shaft diameter will be: a. 160 mm b. 74 mm C. 145 mm d. 92.5 mm e. 60 mm f. 66 mm