Table 17.1 Resistivities and Temperature Coefficients of Resistivityfor Various Materials (at 20°C)Temperature Coefficientof Resistivity[('C)-']Resistivity(N• m)MaterialSilver1.59 x 10-81.7 x 10-83.8 x 10-33.9 x 10-3CopperGold2.44 X 10-83.4 X 10-33.9 x 10-34.5 x 10-35.0 x 10-33.92 x 103.9 x 10Aluminum2.82 x 10-8Tungsten5.6 x 10-8Iron10.0 x 10-8Platinum11 x 10-822 x 10-8150 x 10-83.5 x 10-5-3Lead-3Nichrome"0.4 x 10-3-0.5 x 10-3-48 x 10-3- 75 x 10-3CarbonGermanium0.46Silicon640Glass1010-1014Hard rubber=1013101575 x 1016SulfurQuartz (fused)*A nickel-chromium alloy commonly used in heating elements.

Question
Asked Dec 19, 2019
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A wire 50.0 m long and 2.00 mm in diameter is connected
to a source with a potential difference of 9.11 V, and the current
is found to be 36.0 A. Assume a temperature of 20°C and,
using Table 17.1, identify the metal out of which the wire is
made.

Table 17.1 Resistivities and Temperature Coefficients of Resistivity
for Various Materials (at 20°C)
Temperature Coefficient
of Resistivity
[('C)-']
Resistivity
(N• m)
Material
Silver
1.59 x 10-8
1.7 x 10-8
3.8 x 10-3
3.9 x 10-3
Copper
Gold
2.44 X 10-8
3.4 X 10-3
3.9 x 10-3
4.5 x 10-3
5.0 x 10-3
3.92 x 10
3.9 x 10
Aluminum
2.82 x 10-8
Tungsten
5.6 x 10-8
Iron
10.0 x 10-8
Platinum
11 x 10-8
22 x 10-8
150 x 10-8
3.5 x 10-5
-3
Lead
-3
Nichrome"
0.4 x 10-3
-0.5 x 10-3
-48 x 10-3
- 75 x 10-3
Carbon
Germanium
0.46
Silicon
640
Glass
1010-1014
Hard rubber
=1013
1015
75 x 1016
Sulfur
Quartz (fused)
*A nickel-chromium alloy commonly used in heating elements.
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Table 17.1 Resistivities and Temperature Coefficients of Resistivity for Various Materials (at 20°C) Temperature Coefficient of Resistivity [('C)-'] Resistivity (N• m) Material Silver 1.59 x 10-8 1.7 x 10-8 3.8 x 10-3 3.9 x 10-3 Copper Gold 2.44 X 10-8 3.4 X 10-3 3.9 x 10-3 4.5 x 10-3 5.0 x 10-3 3.92 x 10 3.9 x 10 Aluminum 2.82 x 10-8 Tungsten 5.6 x 10-8 Iron 10.0 x 10-8 Platinum 11 x 10-8 22 x 10-8 150 x 10-8 3.5 x 10-5 -3 Lead -3 Nichrome" 0.4 x 10-3 -0.5 x 10-3 -48 x 10-3 - 75 x 10-3 Carbon Germanium 0.46 Silicon 640 Glass 1010-1014 Hard rubber =1013 1015 75 x 1016 Sulfur Quartz (fused) *A nickel-chromium alloy commonly used in heating elements.

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Given Info: The wire has length 50.0 m and diameter 2.00 mm. The potential difference between ends of wire is 9.11 V and current passes is 36.0 A The wire is at 20°C, The wire has length 50.0 m and diameter 2.00 mm. The potential difference between ends of wire is 9.11 V and current passes is 36.0 A The wire is at 20°C

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Explanation: Formula to calculate the resistance of wire is, AV R Ris the resistance of wire, AV is the potential difference across the ends of wire, I is the current through the wire., Substitute 9.11 V for AV and 36.0 A for I in the above equation to find R, 9.11 V 36.0 A = 0.253 N Therefore, the resistance of wire is 0.253 N

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Formula to calculate the resistivity of wire is, RA p= pis the resistivity of the material of wire, A is the area of cross section of wire, l is the length of the coil, Area of circular cross section of wire is given by ad A = 4 d is the diameter of the wire Substitute equation for area in the above equation to rewrite p Rnd? 41

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