temperature: (Choose from numbers 1 – 6 below) (i) CH3CH2CH2OH (ii) HOCH2CH(OH)CH2OH (iii) HOCH2CH2OH 1. ii < iii < i 2. i < iii < ii 3. i < ii < iii 4. iii < ii < i 5. ii < i < iii 6. iii < i < ii
QUESTION 2
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a) i) Which substance has the lower boiling point PH3 or NH3? (Write formula with numbers & letters on the same level—no sub/superscripts, e.g., Mg3N2 would be written as Mg3N2).
ii) As strength of interparticle forces decreases boiling point (increases or decreases)? (choose one)
Thus the answer to a) (i) is because (choose from A - E)A. NH 3 has weaker H-bonds than PH 3 .B. NH 3 is lighter than PH 3 and therefore would boil first.C. the IM force in PH 3 (dipole-dipole) is stronger than the H-bonding in NH 3 .D. the dominant dipole-dipole forces in PH 3 are weaker than the H-bonding in NH 3 .E. the covalent bonding is this molecule is stronger than the bond in the other molecule.
b) i) Which substance has the higher viscosity Xe or I2? (Write formula with numbers & letters on the same level—no sub/superscripts, e.g., Mg3N2 would be written as Mg3N2)
ii) As strength of interparticle forces increases viscosity (increases or decreases)? (choose one)
Thus the answer to b) (i) is because (choose from A - E)A. it has weaker london forces than the other molecule.B. it has stronger london forces than the other molecule.C. it has stronger covalent bonds than the other molecule.D. it is a nonpolar molecule while the other molecule is polar.E. it is polar while the other molecule is not
c) i) Which substance has the slower evaporation CH4 or H2S? (Write formula with numbers & letters on the same level—no sub/superscripts, e.g., Mg3N2 would be written as Mg3N2)
ii) As strength of interparticle forces increases rate of evaporation (increases or decreases)? (choose one)
Thus the answer to c) (i) is because (choose from A - E)A. H 2 S has stronger H-bonds than CH 4 .B. H 2 S is lighter than PH 3 and therefore would evapoarte firstC. H 2 S has stronger dipole-dipole forces than the weaker london forces in CH 4 .D. CH 4 has more H-bonds than H 2 S.E. CH 4 is polar while H 2 S is nonpolar.
d) Rank the following compounds in order of increasing (lowest to highest) vapor pressure at a given temperature: (Choose from numbers 1 – 6 below)
(i) CH3CH2CH2OH (ii) HOCH2CH(OH)CH2OH (iii) HOCH2CH2OH1. ii < iii < i2. i < iii < ii3. i < ii < iii4. iii < ii < i5. ii < i < iii6. iii < i < ii
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