The 2-kg particle shown is restricted to move in the x-y plane. The resultant force acting on the object is givenas a function of time by ΣF = 6i + 2tj (N). Initially, the object's position is r = 5i + 3j (m)and its velocity is v =121 + 5j (m/s). What is the object's position at t = 8 s?ΣΕX

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The 2-kg particle shown is restricted to move in the x-y plane. The resultant force acting on the object is given. as a function of time by EF = 6i + 2tj (N). Initially, the object's position is r = 5i + 3j (m)and its velocity is v= 121 + 5j (m/s). What is the object's position at t = 8 s? ΣΕ X

The 2-kg particle shown is restricted to move in the x-y plane. The resultant force acting on the object is given. as a function of time by EF = 6i + 2tj (N). Initially, the object's position is r = 5i + 3j (m)and its velocity is v= 121 + 5j (m/s). What is the object's position at t = 8 s? ΣΕ X

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)

5th Edition

ISBN:9781305084766

Author:Saeed Moaveni

Publisher:Saeed Moaveni

Chapter10: Force And Force-related Variables In Engineering

Section: Chapter Questions

Problem 28P

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Question

The 2-kg particle shown is restricted to move in the x-y plane. The resultant force acting on the object is given
as a function of time by ΣF = 6i + 2tj (N). Initially, the object's position is r = 5i + 3j (m)and its velocity is v =
121 + 5j (m/s). What is the object's position at t = 8 s?
ΣΕ
X

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