Question
Asked Oct 13, 2019
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The 2-D Cartesian position vector r for a particle in motion is shown below in meters where t is in seconds:

r =  7 t- 4 t+ 8 t3  i   +   4 t+ 5 t- 3 t5  j

At time = 3 seconds, determine the magnitude of the acceleration vector in m/s/s. 

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Expert Answer

Step 1

The velocity of particle is

di
dt
d
(7-4 +8 )i+ (4r +5 -3)i
=(35t-16t +24/)i+(12 +20 -15t* )j
dt
help_outline

Image Transcriptionclose

di dt d (7-4 +8 )i+ (4r +5 -3)i =(35t-16t +24/)i+(12 +20 -15t* )j dt

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Step 2

The acceleration of...

dv
dt
(35t -16 +24/i+ (12r +20f -15f* )j
dt
i+ (24t+ 602 - 60r)i
(140t -48248t
a(3780-432+144)i+(72+540-1620)
= 3492î -1008
t-3s
help_outline

Image Transcriptionclose

dv dt (35t -16 +24/i+ (12r +20f -15f* )j dt i+ (24t+ 602 - 60r)i (140t -48248t a(3780-432+144)i+(72+540-1620) = 3492î -1008 t-3s

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