The 33-kg crate is stationary when the force Pis applied. Determine the resulting acceleration of the crate if (a) P-0, (b) P- 143 N. and (c) P- 322 N. The acceleration is positive if up the slope, negative if down the slope. [H, = 0.37 H = 0.29 33 kg Part 1 Correct Part (a). We need to decide if the block moves. The easy way to make this decision is to assume that the block does not move and then to test this assumption. If P-0, what friction force Fis needed to keep the block from moving? mg Answer: F- 136.014 N eTextbook and Media Hint Attempts: 2 of 3 used Part 2 Correct Part (a). P-0. What is the maximum friction force Fmay that is availalbe for this situation? mg Answer: Fmax- 108.55 N

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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v Correct
Part (a). P - 0. Since the force F needed to keep the crate from moving is larger than the maximum friction force Fmax that is
available, we know that the crate does move. Solve for the acceleration of the block. We will assume that the acceleration is
positive if it moves up the slope.
mg
N
Answer:a -
-1.57
m/s?
eTextbook and Media
Hint
Attempts: 1 of 3 used
Part 4
Part (b). Follow the same procedure with P- 143 N. What is the friction force Fneeded to keep the block from slipping? If the
friction force F for this case is in the same direction as that shown in the sketch, enter a positive number. If the friction force F for
this case is in the opposite direction as that shown in the sketch, enter a negative value for F. What is the magnitude of the
maximum friction force Fmax that can be produced in this situation (enter a positive value for Fmax)?
mg
Answers:
F-
i
Fmax -
i
Transcribed Image Text:v Correct Part (a). P - 0. Since the force F needed to keep the crate from moving is larger than the maximum friction force Fmax that is available, we know that the crate does move. Solve for the acceleration of the block. We will assume that the acceleration is positive if it moves up the slope. mg N Answer:a - -1.57 m/s? eTextbook and Media Hint Attempts: 1 of 3 used Part 4 Part (b). Follow the same procedure with P- 143 N. What is the friction force Fneeded to keep the block from slipping? If the friction force F for this case is in the same direction as that shown in the sketch, enter a positive number. If the friction force F for this case is in the opposite direction as that shown in the sketch, enter a negative value for F. What is the magnitude of the maximum friction force Fmax that can be produced in this situation (enter a positive value for Fmax)? mg Answers: F- i Fmax - i
The 33-kg crate is stationary when the force Pis applied. Determine the resulting acceleration of the crate if (a) P- 0, (b) P- 143 N.
and (c) P- 322 N. The acceleration is positive if up the slope, negative if down the slope.
[H, = 0.37
H = 0.29
33 kg
25°
Part 1
v Correct
Part (a). We need to decide if the block moves. The easy way to make this decision is to assume that the block does not move and
then to test this assumption. If P- 0, what friction force Fis needed to keep the block from moving?
mg
Answer: F-
136.014
N
eTextbook and Media
Hint
Attempts: 2 of 3 used
Part 2
v Correct
Part (a). P- 0. What is the maximum friction force Fmey that is availalbe for this situation?
mg
N
Answer: Fmax -
108.55
N
Transcribed Image Text:The 33-kg crate is stationary when the force Pis applied. Determine the resulting acceleration of the crate if (a) P- 0, (b) P- 143 N. and (c) P- 322 N. The acceleration is positive if up the slope, negative if down the slope. [H, = 0.37 H = 0.29 33 kg 25° Part 1 v Correct Part (a). We need to decide if the block moves. The easy way to make this decision is to assume that the block does not move and then to test this assumption. If P- 0, what friction force Fis needed to keep the block from moving? mg Answer: F- 136.014 N eTextbook and Media Hint Attempts: 2 of 3 used Part 2 v Correct Part (a). P- 0. What is the maximum friction force Fmey that is availalbe for this situation? mg N Answer: Fmax - 108.55 N
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