The 4.90 A current through a 1.50 H inductor is dissipated by a 1.9O N resistor in a circuit like that in the figure below withthe switch in position 2.I0.6321.0.368/,0-t = L/R 2t3t47T = L/R 2t3747(a)(b)(c)(a) What is the initial energy (in J) in the inductor?(b) How long will it take (in s) the current to decline to 5.00% of its initial value?(c) Calculate the average power (in W) dissipated, and compare it with the initial power dissipated by the resistor.W(ratio of initial power to average power)

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The 4.90 A current through a 1.50 H inductor is dissipated by a 1.90 a resistor in a circuit like that in the figure below with the switch in position 2. 0.6321, 0.368/, O r- LR 2r 3r 4r O r= LR 2r 3r 4: (b) (c) (a) What is the initial energy (in ) in the inductor? (b) How long will it take (in s) the current to decline to 5.00% of its initial value? (c) Calculate the average power (in W) dissipated, and compare it with the initial power dissipated by the resistor. (ratio of initial power to average power)

The 4.90 A current through a 1.50 H inductor is dissipated by a 1.90 a resistor in a circuit like that in the figure below with the switch in position 2. 0.6321, 0.368/, O r- LR 2r 3r 4r O r= LR 2r 3r 4: (b) (c) (a) What is the initial energy (in ) in the inductor? (b) How long will it take (in s) the current to decline to 5.00% of its initial value? (c) Calculate the average power (in W) dissipated, and compare it with the initial power dissipated by the resistor. (ratio of initial power to average power)

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter31: Inductance

Section: Chapter Questions

Problem 1P

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