The amount of heat absorbed by the solution can be found using the equation q = m x SH x AT. It can also be written as qsolution = msolution X SHsolution X ATsolution: We can assume that the specific heat of the solution is the same as the specific heat of water which is 1.00 cal/(g °C). Data Table Tfinal Mass of Zn HCI Volume Tinitial final 0.55 g 100.0 ml 20.0 °C 23.10c Which of the following shows the correct calculation of qsolution? O a. 100.0 mL x 1.00 cal x 3.1°C g°C O b. 107 grams x 1.00 cal х 3.10С g °C cal х 3.1°С g °C 0.55 grams x 1.00 O d. cal 107 grams x 1.00 X 23.1°C g °C

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.64QE: Dissolving 6.00 g CaCl2 in 300 mL of water causes the temperature of the solution to increase by...
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The amount of heat absorbed by the solution can be found using the equation
q = m x SH x AT. It can also be written as qsolution = msolution X SHsolution X
ATsolution: We can assume that the specific heat of the solution is the same as
the specific heat of water which is 1.00 cal/(g °C).
Data Table
Mass of Zn HCI Volume Tinitial
Tfinal
0.55 g
100.0 mL
20.0 °C 23.1°c
Which of the following shows the correct calculation of qsolution?
O a. 100.0 mL x 1.00 Cal x 3.1°C
g°C
Ob.
107 grams x 1.00
cal
x 3.1°C
g °C
0.55 grams x 1.00
cal
х 3.1°C
g °C
d.
107 grams x 1.00
cal
X 23.1°C
g °C
je
Next page
Transcribed Image Text:1ml The amount of heat absorbed by the solution can be found using the equation q = m x SH x AT. It can also be written as qsolution = msolution X SHsolution X ATsolution: We can assume that the specific heat of the solution is the same as the specific heat of water which is 1.00 cal/(g °C). Data Table Mass of Zn HCI Volume Tinitial Tfinal 0.55 g 100.0 mL 20.0 °C 23.1°c Which of the following shows the correct calculation of qsolution? O a. 100.0 mL x 1.00 Cal x 3.1°C g°C Ob. 107 grams x 1.00 cal x 3.1°C g °C 0.55 grams x 1.00 cal х 3.1°C g °C d. 107 grams x 1.00 cal X 23.1°C g °C je Next page
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