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The area of a sector of a circle (shaded region) is given by A = If the area of the shaded sector is proportional to the fifth power of the radius, express in terms of r. Use k as the proportionality constant. O 0(r) = 2kr5 8(r) = 2kr¹0 8(r) = 2kr² 2kr6 O 8(r) = 12/201². Oe(r) = 2kr8 Ⓒ8(r) = 2kr³

The area of a sector of a circle (shaded region) is given by A = If the area of the shaded sector is proportional to the fifth power of the radius, express in terms of r. Use k as the proportionality constant. O 0(r) = 2kr5 8(r) = 2kr¹0 8(r) = 2kr² 2kr6 O 8(r) = 12/201². Oe(r) = 2kr8 Ⓒ8(r) = 2kr³

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter2: Functions And Graphs
Section2.6: Proportion And Variation
Problem 18E
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The area of a sector of a circle (shaded region) is given by A = 201². N If the area of the shaded sector is proportional to the fifth power of the radius, express in terms of r. Use k as the proportionality constant. 8(r) = 2kr5 8(r) = 2kr¹0 8(r) = 2kr² 8(r) = 2kr6 0(r) = 2kr8 8(r) = 2kr³
Transcribed Image Text:The area of a sector of a circle (shaded region) is given by A = 201². N If the area of the shaded sector is proportional to the fifth power of the radius, express in terms of r. Use k as the proportionality constant. 8(r) = 2kr5 8(r) = 2kr¹0 8(r) = 2kr² 8(r) = 2kr6 0(r) = 2kr8 8(r) = 2kr³
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