B4. A 6 pole DC shunt generator with lapwound armature having 384 conductors, hasto supply a load of 514 lamps each of 100 Wat 250 V. Allowing 10 V for the voltage dropin the connecting leads between thegenerator and the load with each brush dropof 2 V. The flux per pole is 39 mWb, Ra = 0.12ohms and Rsh = 75 ohms. Calculate thearmature current and the speed at which thegenerator should be driven. [-The armature current isThe speed of machine is

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Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A 4-pole lap -wound dc generator is designed to have an average airgap flux density of 0 .8 T. The armature winding resistance is 0 .3 Ω, and the brush contact drop is 1 V. There is a slight fault in the magnetic circuit which causes the emfs in two of the paths to be 5 %more than the nominal value, and the emfs in the other two paths 5 %less . a) If the generator supplies a full load of 4 .5 kw at 150 V, find the nominaland actual values of path emfs, coil currents, and armature copper loss. b) Find the nominal and actual values of coil currents and armature copperloss when the generator has no external load.
A 35 kW, 400 V, short shunt, compound dc generator has a full load efficiency of 85 %. If the resistance of the armature and interpole is 0.35 ohm and that of the series and shunt fields are 0.15 ohm and 220 ohms respectively. Calculate the following: Output of the prime mover = kW Power developed in the armature = kw Total Copper Losses = kw Combined bearing friction, windage and core loss = kw
A 18 kW shunt generator having an armature circuit resistance of 0.5 ohm and a fieldresistance of 125 ohm, generates a terminal voltage of 250 V at full load with a brushloss of 1 V per brush. Assuming the iron, friction and windage losses amount to 1.5kW. Determine the efficiency of the generator. (Show all calculations of Currents,Emf, Powers, Power losses, ext.)
A series generator having a combined armature and field resistance of 0.4 ohm usrunning at 1000 rpm and delivering 5.5 kW at a terminal voltage of 110 V. If thespeed is raised to 1500 rpm and load adjusted to 10 kW, find the new terminalvoltage. Assume the machine is working on straight line portion of magnetizationcharacteristics.
please answer in bond paper 3. A long-shunt, four pole, 1500-W, 250-V, duplex wave-wound DC compound generator with the rated speed of 500 r.p.m., has a shunt field resistance of 100 Ω, a series field resistance of 0.05 Ω and an armature resistance of 0.2 Ω. If the flux per pole is 48.798 mWb and a total of 620 conductors, calculate the following: (a) the generated voltage, (b) the field currents, (c) the power generated in the armature.
A shunt generator has an output of 22 kW at a terminal voltage of 220 V. armature and shunt field resistances are 0.05 ohm and 44 ohms, respectively. If the copper loss is equal to the core, friction and windage losses at this load, the over-all efficiency of this generator is nearest to
The armature winding resistance of a long shunt connected DC generator is 0.4ohm, the resistances of the shunt and serial field windings are 125 ohms and 0.1 ohms, respectively. While the generator supplies 8KW of power to the load it feeds, which is the voltage it produces since the output voltage is 250V?
A 12-kW, 250-V dc. shunt generator has armature and field resistances of 0.68 ohm and 120 ohm. respectively. Determine the total armature power developed in generator.
A 25kW, 250V DC shunt generator has armature and field resistances of 0.06 ohm and 100 ohm respectively. Determine the total armature power developed when working (i) as a generator delivering 25kW output and (ii) as a motor taking 25kW.
A 1500 kW, 550 V, 16 pole generator runs at 150 rev. per min. What must be the useful flux if there are 2500 conductors lap-connected and the full-load copper losses being 25 kW? Calculate the area of the pole shoe if the gap density has a uniform value of 0.9 wb/m2 and find the no-load terminal voltage, neglecting armature reaction and change in speed.
A 250 V shunt generator has a full load armature current of 40 A, under these conditions the losses are: FW = 200 watts, shunt field = 100 watts, core = 260 watts, brush contact = 120 watts, armature copper = 400 watts. For operation at maximum efficiency, when the constant losses are equal to those losses that vary as the square of the load, calculate the maximum efficiency.
B4. A 4 pole DC shunt generator with wave wound armature having 390 conductors, has to supply a load of 508 lamps each of 100 W at 250 V. Allowing 10 V for the voltage drop in the connecting leads between the generator and the load with cach brush drop of 2 V. The flux per pole is 32 mWb, Ra = 0.23 ohms and Rsh = 73 ohms. Calculate (a) the armature current and (b) the speed at which the generator should be driven.

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The armature current is The speed of machine is