THE ASQ-3 is a standardized screeing tool. Scores on each domian of the screening tool, communication , gross motor, fine motor, problem solving, and personal - social are normally distributed, and each have a standard deviation for each age group.The mean problem sovling score of 3 years old is 48.7, with a stadard deviation of 9.2.You believe that 3 year old who attend a particular pre school have a better than average problem solving skills.. All of the 3 year old attending that pre school are screened using ASQ-3. Here is the sample data from a particular pre school program Scores: 55, 67,54, 59, 65, 53, 49 50, 51, 48 ,65, 59, 61, 55, 67, 56, 60, 65, 48, 63, 53, 49, 65, 62, 57. Test the hypothesis at the 5 % level significance. (alpha =0.05) using the five step procedure given below. step1 .Specify the null hypothese step 2: specify the alternative hypothese; step3: set the alpha level step4 : calculate the test statistic and the corresponding p value step5: draw up a conclusion clearly state the null and alternative hypotheses. Round up answer to 2 decimal places Based on the Z (calculated) score obtained above , complete the following table by indicating the correct conclusion. alpha type of hypothesis type of test Z(critical) conclusion .05 Non-directional two tailed 1.96 .01 directional one tail 2.33 .01 non-diectional two tail 2.575
THE ASQ-3 is a standardized screeing tool. Scores on each domian of the screening tool, communication , gross motor, fine motor, problem solving, and personal - social are
distributed, and each have a standard deviation for each age group.The mean problem sovling score
of 3 years old is 48.7, with a stadard deviation of 9.2.You believe that 3 year old who attend a
particular pre school have a better than average problem solving skills.. All of the 3 year old attending that pre school are screened using ASQ-3. Here is the sample data from a particular pre school program
Scores: 55, 67,54, 59, 65, 53, 49 50, 51, 48 ,65, 59, 61, 55, 67, 56, 60, 65, 48, 63, 53, 49, 65, 62, 57.
Test the hypothesis at the 5 % level significance. (alpha =0.05) using the five step procedure given below.
step1 .Specify the null hypothese
step 2: specify the alternative hypothese;
step3: set the alpha level
step4 : calculate the test statistic and the corresponding p value
step5: draw up a conclusion
clearly state the null and alternative hypotheses. Round up answer to 2 decimal places
Based on the Z (calculated) score obtained above , complete the following table by indicating the
correct conclusion.
alpha type of hypothesis type of test Z(critical) conclusion
.05 Non-directional two tailed 1.96
.01 directional one tail 2.33
.01 non-diectional two tail 2.575
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