The assigned buffer will be a 0.10 M, pH 6.70 buffer. The only available reagents are: 0.20 M NaH2PO4, 0.20 M Na2HPO4, 1.0 M HCl and 1.0 M NaOH Calculate the necessary amounts needed to prepare the assigned buffer. (pKa1=2.15, pКаa37.20, pКаз-12.68) Н,РОд (аq) H*(aq) + H,PO, (aq) pКа1-2.15 -2 НАРО (аq) H*(aq) + HPO4? (aq) pKa2=7.20 pКаз-12.68 НРО,? (аq) -2 -3 H*(aq) + HPO4* (aq)

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter14: Equilibria In Acid-base Solutions
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The assigned buffer will be a 0.10 M, pH 6.70 buffer.
The only available reagents are: 0.20 M NaH2PO4, 0.20 M Na2HPO4, 1.0 M HCI and 1.0 M NAOH.
Calculate the necessary amounts needed to prepare the assigned buffer. (pKa1=2.15,
pКаz37.20, рКаз-12.68)
H;PO4 (aq)
H*(aq) + H2PO4 (aq)
pkа1-2.15
H*(aq) + HPO4? (aq)
H,PO, (aq)
-2
pKa2=7.20
pКаз-12.68
НРО,2 (аq)
H*(aq) + HPO4* (aq)
Transcribed Image Text:The assigned buffer will be a 0.10 M, pH 6.70 buffer. The only available reagents are: 0.20 M NaH2PO4, 0.20 M Na2HPO4, 1.0 M HCI and 1.0 M NAOH. Calculate the necessary amounts needed to prepare the assigned buffer. (pKa1=2.15, pКаz37.20, рКаз-12.68) H;PO4 (aq) H*(aq) + H2PO4 (aq) pkа1-2.15 H*(aq) + HPO4? (aq) H,PO, (aq) -2 pKa2=7.20 pКаз-12.68 НРО,2 (аq) H*(aq) + HPO4* (aq)
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