Question
Asked Nov 13, 2019
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The atmospheric pressure above a swimming pool changes from 755 to 765 mm of mercury. The bottom of the pool is a rectangle (12 m × 24 m). By how much does the force on the bottom of the pool increase?

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Expert Answer

Step 1

Given:

The area of the pool's bottom is
A (12m)x (24 m)
The initial atmospheric pressure is,
P 755mm
The final atmospheric pressure is,
P 765 mm
The change in the pressure is,
AP P-P
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The area of the pool's bottom is A (12m)x (24 m) The initial atmospheric pressure is, P 755mm The final atmospheric pressure is, P 765 mm The change in the pressure is, AP P-P

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Step 2

We know that change in pressure i...

AF
AP =
or, AF A AP
-A (P, - P
or
- (12х24) m? (765 - 755) mm
or
-(288) m* -(10тт)
or,
133.3N/m2
= ( 288)m210mm
or
тm
1mm 133.3N / m2 of mercury]
133.3N/m2
%3 (288) m? 10ттx.
or
тm
or, AF 3.84 x103N
help_outline

Image Transcriptionclose

AF AP = or, AF A AP -A (P, - P or - (12х24) m? (765 - 755) mm or -(288) m* -(10тт) or, 133.3N/m2 = ( 288)m210mm or тm 1mm 133.3N / m2 of mercury] 133.3N/m2 %3 (288) m? 10ттx. or тm or, AF 3.84 x103N

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