The average waiting ime for a patient to be cared for at the emergency unit of that hospital is also known to follow an expone distribution. A patient walked into the emergency unit at 4pm. a) Find the probability that the patient will be cared for in the next hour. b) Find the probability that the patient will be cared for between 6pm and 8pm.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.9: Independent And Dependent Events
Problem 3C
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Problem 14
The average waiting time for a patient to receive care at the emergency unit of a hospital is 3 hours. The waiting
time for a patient to be cared for at the emergency unit of that hospital is also known to follow an exponential
distribution. A patient walked into the emergency unit at 4pm.
a) Find the probability that the patient will be cared for in the next hour.
b) Find the probability that the patient will be cared for between 6pm and 8pm.
Transcribed Image Text:Problem 14 The average waiting time for a patient to receive care at the emergency unit of a hospital is 3 hours. The waiting time for a patient to be cared for at the emergency unit of that hospital is also known to follow an exponential distribution. A patient walked into the emergency unit at 4pm. a) Find the probability that the patient will be cared for in the next hour. b) Find the probability that the patient will be cared for between 6pm and 8pm.
Expert Solution
Step 1

Given:

Average care time, λ=3 hours

The waiting time follows exponential distribution. So, probability formula for exponential distribution;

P X=r=e-λ λrr !λ=Average or meanr = Number of sucsess

A patient walked into emergency unit at 4 pm.

Step 2

(a) Probability that the patient will be cared for in the next hour:

Using exponential formula given above:

P (Patient will be cared for next hour)=P (X=1)

Therefore,

P (X=1)=e-3. 311 !=e-3×31    (Note: Here, r=1 hour, λ=3)P (X=1)=0.149

Therefore, required probability is 0.149.

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