The base of a three-dimensional figure is bound by the circle x² + y² = 9. Vertical cross sections that are perpendicular to the y-axis are isosceles triangles with height equal to 3. Algebraically, find the area of each triangle. 54- O A(Y) = O A(y) = 3 V 9 O A(Y) = 2 19-y² O A(y) = √√√9-y²

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 68E
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The base of a three-dimensional figure is bound by the circle x² + y² = 9. Vertical cross sections that are perpendicular to the y-axis are
isosceles triangles with height equal to 3.
Algebraically, find the area of each triangle.
Y
5
4
24
X
543√2 23 45
A(y) =
A(y) = 3 V
19 - y²
A(y) = 2√√/9 - y²
A(y):
= 1/2 √√√/9-y²
19
9 - y²
Transcribed Image Text:The base of a three-dimensional figure is bound by the circle x² + y² = 9. Vertical cross sections that are perpendicular to the y-axis are isosceles triangles with height equal to 3. Algebraically, find the area of each triangle. Y 5 4 24 X 543√2 23 45 A(y) = A(y) = 3 V 19 - y² A(y) = 2√√/9 - y² A(y): = 1/2 √√√/9-y² 19 9 - y²
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