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The base of a three-dimensional figure is bound by the circle x2 + y? = 9. Vertical cross sections that are perpendicular to the x-axis are rectangles with height equal to twice the width. Algebraically, find the area of each rectangle. 54

The base of a three-dimensional figure is bound by the circle x2 + y? = 9. Vertical cross sections that are perpendicular to the x-axis are rectangles with height equal to twice the width. Algebraically, find the area of each rectangle. 54

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.5: Multiplication With The Addition-or-subtraction Method
Problem 28P
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The base of a three-dimensional figure is bound by the circle x2 + y? = 9. Vertical cross sections that are perpendicular to the x-axis are rectangles with height equal to twice the width. Algebraically, find the area of each rectangle. 54 2 4 5 O A(x) = 8(9- x²) O A(x) = (9 + x?) O A(x) = 2(9-x²) O A(x) = 2(9 + x²)
Transcribed Image Text:The base of a three-dimensional figure is bound by the circle x2 + y? = 9. Vertical cross sections that are perpendicular to the x-axis are rectangles with height equal to twice the width. Algebraically, find the area of each rectangle. 54 2 4 5 O A(x) = 8(9- x²) O A(x) = (9 + x?) O A(x) = 2(9-x²) O A(x) = 2(9 + x²)
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