Question
Asked Sep 26, 2019
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The best leaper in the animal kingdom is the puma, which can jump to a height of 3.7 m when leaving the ground at an angle of 45°. With what speed must the animal leave the ground to reach that height?

__ m/s

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Expert Answer

Step 1

The puma will be in a projectile motion. The equation for the maximum height achieved by a projectile is given by

h =
2g
Here, his the maximum height reached, v is the initial speed, 0 is the initial angle of launch and g
is the acceleration due to gravity
Rewrite the above equation for v,
2gh=v sin2 e
2gh
sin e
2gh
sin e
The value of g is 9.80 m/s2 .
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h = 2g Here, his the maximum height reached, v is the initial speed, 0 is the initial angle of launch and g is the acceleration due to gravity Rewrite the above equation for v, 2gh=v sin2 e 2gh sin e 2gh sin e The value of g is 9.80 m/s2 .

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Step 2

Substitute the numerical values...

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