The biological relationship between the growth for the fish population and the size of the fish population is g= 12S(1-S/4) where g is the growth of the fish population and S is the size of the population. The size of the harvest is a function of the amount of human effort expended b = 3ES where E is the level of effort. Market price of fish per unit is $100 and a constant marginal cost of effort is $40. We can derive the free-access equilibrium effort level E f by setting the net benefits function equal to zero. Then, Ef= in one decimal place. .Hint: Write the number

Managerial Economics: Applications, Strategies and Tactics (MindTap Course List)
14th Edition
ISBN:9781305506381
Author:James R. McGuigan, R. Charles Moyer, Frederick H.deB. Harris
Publisher:James R. McGuigan, R. Charles Moyer, Frederick H.deB. Harris
Chapter7: Production Economics
Section: Chapter Questions
Problem 9E
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The biological relationship between the growth for the fish population and the size of the fish population is
g = 12S(1 - S/4)
where g is the growth of the fish population and S is the size of the population. The size of the harvest is a function of the amount of human effort expended
b = 3ES
where E is the level of effort. Market price of fish per unit is $100 and a constant marginal cost of effort is $40.
We can derive the free-access equilibrium effort level Ef by setting the net benefits function equal to zero. Then, E f =
in one decimal place.
Hint: Write the number
Transcribed Image Text:The biological relationship between the growth for the fish population and the size of the fish population is g = 12S(1 - S/4) where g is the growth of the fish population and S is the size of the population. The size of the harvest is a function of the amount of human effort expended b = 3ES where E is the level of effort. Market price of fish per unit is $100 and a constant marginal cost of effort is $40. We can derive the free-access equilibrium effort level Ef by setting the net benefits function equal to zero. Then, E f = in one decimal place. Hint: Write the number
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