The block as shown in Figure 3.6 has a weight of 250 N, which is inclined at 30° to the horizontal. Calculate the frictional force acting at the surface of contact µs = 0.6.the answe Ff=129.91N 3. The block as shown in Figure 3.6 has a weight of 250 N, which is inclined at 30° to thehorizontal. Calculate the frictional force acting at the surface of contact Hs = 0.6.60 NFFigure 3.6

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Answered: The block as shown in Figure 3.6 has a…

The block as shown in Figure 3.6 has a weight of 250 N, which is inclined at 30° to the horizontal. Calculate the frictional force acting at the surface of contact µs = 0.6.

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter7: Dry Friction

Section: Chapter Questions

Problem 7.50P: The block of weight W is pulled by the force P inclined at the angle to the horizontal. Find the...

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Question

The block as shown in Figure 3.6 has a weight of 250 N, which is inclined at 30° to the horizontal. Calculate the frictional force acting at the surface of contact µ_s = 0.6.
the answe Ff=129.91N

3. The block as shown in Figure 3.6 has a weight of 250 N, which is inclined at 30° to the
horizontal. Calculate the frictional force acting at the surface of contact Hs = 0.6.
60 N
F
Figure 3.6

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