The boiling point of a solution of 1.056 moles of an electrolyte dissolved in 1399 g of benzene is 83.76 °C. What is the van't Hoff factor for this solution if pure benzene boils at 80.11 °C and its Kb value is 2.53 °C/m?

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.82QE: The freezing point of a 0.031-m solution of copper(II) sulfate in water is 0.075 C. (a) Calculate...
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The boiling point of a solution of 1.056 moles of an
electrolyte dissolved in 1399 g of benzene is 83.76
°C. What is the van't Hoff factor for this solution if
pure benzene boils at 80.11 °C and its Kb value is
2.53 °C/m?
Transcribed Image Text:The boiling point of a solution of 1.056 moles of an electrolyte dissolved in 1399 g of benzene is 83.76 °C. What is the van't Hoff factor for this solution if pure benzene boils at 80.11 °C and its Kb value is 2.53 °C/m?
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