The bottom face: o (r, 0) = (r1(r, 0), y1 (r,0), z1 (r, 0) where 0 <0< 27, 0

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter10: Analytic Geometry
Section10.6: The Three-dimensional Coordinate System
Problem 21E
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The bottom face: o (r, 0) = (r1(r, 0), y1 (r,0), z1 (r, 0) where 0 <0< 27, 0 <r< 3 and
1(r, 0) =
y1 (r, 0) =
z1(r, 0) = -2
The top face: o2(r, 0) = (x2(r, 0), y2 (r, 0), z2(r, 0) where 0 <0S 27, 0 <r < 3 and
2(r, 0) =
2(r, e) =
z2(r, 0) = 3
The lateral face: o3(6, z) = (a3(0, z), ys (0, z), z3(0, z) where 0 <0< 27, -2 < z< 3 and
3(0)
(0) =
z3(2) =
Then (mind the orientation)
F. ndS =
F(o1).
dr de +
F(o2) ·
dr de +
F(o3)
dz de
ar
ar
Part 2- Using the Divergence Theorem
Transcribed Image Text:The bottom face: o (r, 0) = (r1(r, 0), y1 (r,0), z1 (r, 0) where 0 <0< 27, 0 <r< 3 and 1(r, 0) = y1 (r, 0) = z1(r, 0) = -2 The top face: o2(r, 0) = (x2(r, 0), y2 (r, 0), z2(r, 0) where 0 <0S 27, 0 <r < 3 and 2(r, 0) = 2(r, e) = z2(r, 0) = 3 The lateral face: o3(6, z) = (a3(0, z), ys (0, z), z3(0, z) where 0 <0< 27, -2 < z< 3 and 3(0) (0) = z3(2) = Then (mind the orientation) F. ndS = F(o1). dr de + F(o2) · dr de + F(o3) dz de ar ar Part 2- Using the Divergence Theorem
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