The box plots compare the speeds ofcars traveling on a highway.Speeds of carsNorth• South千+>485256606468727680O The median speed for the cars going North is higher than the median speed for the cars going South.O The maximum speed for the cars going North is higher than the maximum speed for the cars going South.O The interquartile range for the cars going North is higher than the interquartile range for the cars going South.O The lower quartile for the cars goingis lower than the lower quartile for the cars going South.O The interquartile range for the cars going North is 27.O The interquartile range for the cars going South is 9.->278.

In box plot, median is the mid point of data ,so median speed of car going north is less than median…

Answered: The box plots compare the speeds of…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter3: Two-dimensional Kinematics

Section: Chapter Questions

Problem 50PE: Unreasonable Results (a) Find the maximum range of a super cannon that has a muzzle velocity of 4.0...

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You are operating a radio-controlled model car on a vacant tennis court. Your position is the origin oc coordinates, and the surface of the court lies in the xy-plane. The car, which we represent as a point, has x and y-coordinates that vary with time according to x = 2.0 m – (0.25 m/s2)t2 y = (1.0 m/s)t + (0.025 m/s3)t3 1. Find the car’s coordinate’s and distance from you at time t = 2.0 s. A) (1.0m, 2.2 m) r = 2.4 m B) (2.2m, 1.5m) r = 2.7m C) (2.5m, 2.05m) r = 3.2 m D) (2.3m, 1.0m) r = 2.5m 2. The components of the car’s instantaneous velocity are the time derivatives of the coordinates: vx = dx/dt = (-0.25 m/s2)(2t), vy = dy/dt = 1.0 m/s + (0.025 m/s3)(3t2) This can be expressed as velocity vector v = vxî + vyĵ = (-0.5 m/s2)tî + [1.0 m/s + (0.075 m/s3)t2]ĵ 3. What are the components of instantaneous velocity and its…
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