the box that minimize the amount of material used. st, find a formula for the surface area of the box in terms of se. int: use the volume formula to express the height of the box mplify your formula as much as possible. (z) = | xt, find the derivative, A'(x). "(z) =| '(x)

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter59: Areas Of Rectangles, Parallelograms, And Trapezoids
Section: Chapter Questions
Problem 79A
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A box with a square base and open top must have a volume of 42592 cm. We wish to find the dimensions
of the box that minimize the amount of material used.
First, find a formula for the surface area of the box in terms of only æ, the length of one side of the square
base.
[Hint: use the volume formula to express the height of the box in terms of æ.]
Simplify your formula as much as possible.
A(x) =
Next, find the derivative, A'(x).
A' (x) =
Now, calculate when the derivative equals zero, that is, when A'(x) = 0. [Hint: multiply both sides by æ?
A' (x) = 0 when æ =
We next have to make sure that this value of x gives a minimum value for the surface area. Let's use the
second derivative test. Find A"(x).
A"(2) =
Evaluate A"(x) at the x-value you gave above.
NOTE: Since your last answer is positive, this means that the graph of A(æ) is concave up around that
value, so the zero of A' (x) must indicate a local minimum for A(x). (Your boss is happy now.)
Transcribed Image Text:A box with a square base and open top must have a volume of 42592 cm. We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only æ, the length of one side of the square base. [Hint: use the volume formula to express the height of the box in terms of æ.] Simplify your formula as much as possible. A(x) = Next, find the derivative, A'(x). A' (x) = Now, calculate when the derivative equals zero, that is, when A'(x) = 0. [Hint: multiply both sides by æ? A' (x) = 0 when æ = We next have to make sure that this value of x gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(2) = Evaluate A"(x) at the x-value you gave above. NOTE: Since your last answer is positive, this means that the graph of A(æ) is concave up around that value, so the zero of A' (x) must indicate a local minimum for A(x). (Your boss is happy now.)
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