The capacitance of a parallel plate capacitor in vacuum is Co= 8 pF, by inserting a dielectric material between the plates, its capacitance is now C'= 40 pF The electric field was 2.5x105 v/m for the empty capacitor. What is the new magnitude of the electric field with the dielectric between the plates? a) E' = 250 kV/m b) E' = 1000 kV/m c) E' 125 kV/m d) E' = 50 kV/m

The capacitance of a parallel plate capacitor in vacuum is Co= 8 pF, by inserting a dielectric material between the plates, its capacitance is now C'= 40 pF The electric field was 2.5x105 v/m for the empty capacitor. What is the new magnitude of the electric field with the dielectric between the plates? a) E' = 250 kV/m b) E' = 1000 kV/m c) E' 125 kV/m d) E' = 50 kV/m

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter8: Capacitance

Section: Chapter Questions

Problem 61P: The dielectric to be used in a parallel-plate capacitor has a dielectric constant of 3.60 and a...

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