The charge at the origin has a value of Q = +2x10-8 The other 2 charges have values of multiples of q, where q is 1x10-8 C, as shown in the figure (+2q, and +4g). If a = 2 m, what is the total electrostatic force on Q due to the other 2 charged particles? Write your answer in unit vector form. +2.00q a +Q a +4.00q

The charge at the origin has a value of Q = +2x10-8 The other 2 charges have values of multiples of q, where q is 1x10-8 C, as shown in the figure (+2q, and +4g). If a = 2 m, what is the total electrostatic force on Q due to the other 2 charged particles? Write your answer in unit vector form. +2.00q a +Q a +4.00q

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 1OQ: A point charge of 4.00 nC is located at (0, 1.00) m. What is the x component of the electric field...

See similar textbooks

Similar questions

Two particles with charges q1 and q2 are separated by a distance d, and each exerts an electric force on the other with magnitude FE. a. In terms of these quantities, what separation distance would cause the magnitude of the electric force to be halved? b. In terms of these quantities, what separation distance would cause the magnitude of the electric force to be doubled?
Panicle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m, 0), and panicle C of charge 1.00 104 C is at (0, 3.00 m). (a) What is the x-component of the electric force exerted by A on C? (b) What is the y-component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.
Particle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 101 C is at (4.00 m, 0), and particle C of charge 1.00 104 C is at (0, 3.00 in). We wish to find the net electric force on C. (a) What is the x component of the electric force exerted by A on C? (b) What is the y component of the force exerted by A on C? (c) Kind the magnitude of the force exerted by B on C. (d) Calculate the x component of the force exerted by B on C. (e) Calculate the y component of the force exerted by B on C. (f) Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C. (g) Similarly, find the y component of the resultant force vector acting on C. (h) Kind the magnitude and direction of the resultant electric force acting on C.
Panicle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m, 0), and panicle C of charge 1.00 104 C is at (0, 3.00 m). (a) What is the x-component of the electric force exerted by A on C? (b) What is the y-component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.
A point charge of 4.00 nC is located at (0, 1.00) m. What is the x component of the electric field due to the point charge at (4.00, 2.00) m? (a) 1.15 N/C (b) 0.864 N/C (c) 1.44 N/C (d) 1.15 N/C (e) 0.864 N/C
A 1.75-nC charged particle located at the origin is separated by a distance of 0.0825 m from a 2.88-nC charged particle located farther along the positive x axis. If the 1.75-nC particle is kept fixed at the origin, where along the positive x axis should the 2.88-nC particle be located so that the magnitude of the electrostatic force it experiences is twice as great as it was in Problem 27?
Two point charges attract each other with an electric force of magnitude F. If the charge on one of the particles is reduced to one-third its original value and the distance between the particles is doubled, what is the resulting magnitude of the electric force between them? (a) 112F (b) 13F (c) 16F (d) 34F (e) 32F
(a) Two point charges q1 and q23.00 m apart, and their total charge is 20 C. (a) If the force of repulsion between them is 0.075N, what are magnitudes of the two charges? (b) If one charge attracts the other with a force of 0.150 N, what are the magnitudes of the two charges? Note that you may need to solve a quadratic equation to reach your answer.
Three charged particles are located at the corners of an equilateral triangle as shown in Figure P19.9. Calculate the total electric force on the 7.00-C charge.
A sphere has a net charge of 8.05 nC, and a negatively charged rod has a charge of 6.03 nC. The sphere and rod undergo a process such that 5.00 109 electrons are transferred from the rod to the sphere. What are the charges of the sphere and the rod after this process?
Charges A, B, and C are arranged in the xy plane with qA = 5.60 C, qB = 4.00 C, and qC = 2.30 /C (Fig. P23.43). What are the magnitude and direction of the electrostatic force on charge B? Figure P23.43
A circular ring of charge of radius b has a total charge q uniformly distributed around it. Find the magnitude of the electric field in the center of the ring. (a) 0 (b) keq/b2 (c) keq2/b2 (d) keq2/b (e) None of these answers is correct.